High school students across the nation compete in a financial capability challenge each year by taking a National Financial Capability Challenge Exam. Students who score in the top 18 percent are recognized publicly for their achievement by the Department of the Treasury. Assuming a normal distribution, how many standard deviations above the mean does a student have to score to be publicly recognized? (Round your answer to 2 decimal places.)
Need in text format no handwriting thank u
In: Statistics and Probability
Lloyd is completing high school and wondering about his future. He needs to make a choice between pursuing a bachelor’s degree in business or pursuing an MBA. Lloyd lives in two periods, the first relating to his education and the second relating to employment commencing after graduation and extending through retirement. In the first period, he completes his education. In the second period, he works in the labor market. Lloyd determines to attend the University of Utah.
If Lloyd pursues a bachelor’s degree at the U of U, he will spend $52,000 on education in the first period and earn $2.4 million in the second period. If he pursues an MBA, he will spend $139,000 on education in the first period and earn $2.8 million in the second period. Lloyd seeks to maximize his lifetime earnings.
Suppose that Lloyd can lend and borrow money at a 7% rate of interest between the two periods. Which degree will Lloyd pursue? Explain using both mathematic calculation and verbal description.
In: Economics
Scenario
Frank has only had a brief introduction to statistics when he was in high school 12 years ago, and that did not cover inferential statistics. He is not confident in his ability to answer some of the problems posed in the course.
As Frank's tutor, you need to provide Frank with guidance and instruction on a worksheet he has partially filled out. Your job is to help him understand and comprehend the material. You should not simply be providing him with an answer as this will not help when it comes time to take the test. Instead, you will be providing a step-by-step breakdown of the problems including an explanation on why you did each step and using proper terminology.
What to Submit
To complete this assignment, you must first download the word document, and then complete it by including the following items on the worksheet:
Incorrect Answers
Correct any wrong answers. You must also explain the error performed in the problem in your own words.
Partially Finished Work
Complete any partially completed work. Make sure to provide step-by-step instructions including explanations.
Blank Questions
Show how to complete any blank questions by providing step-by-step instructions including explanations.
Your step-by-step breakdown of the problems, including explanations, should be present within the word document provided. You must also include an Excel workbook which shows all your calculations performed.
WORKSHEET:
Deliverable 02 – Worksheet
Instructions: The following worksheet is shown to you by a student who is asking for help. Your job is to help the student walk through the problems by showing the student how to solve each problem in detail. You are expected to explain all of the steps in your own words.
Key:
<i> - This problem is an incorrect. Your job is to find the errors, correct the errors, and explain what they did wrong.
<p> - This problem is partially finished. You must complete the problem by showing all steps while explaining yourself.
<b> - This problem is blank. You must start from scratch and explain how you will approach the problem, how you solve it, and explain why you took each step.
<p> Assume that a randomly selected subject is given a bone density test. Those tests follow a standard normal distribution. Find the probability that the bone density score for this subject is between -1.53 and 1.98
Student’s answer: We first need to find the probability for each of these z-scores using Excel.
For -1.53 the probability from the left is 0.0630, and for 1.98 the probability from the left is 0.9761.
Continue the solution:
|
Finish the problem giving step-by-step instructions and explanations. |
<b> The U.S. Airforce requires that pilots have a height between 64 in. and 77 in. If women’s heights are normally distributed with a mean of 65 in. and a standard deviation of 3.5 in, find the percentage of women that meet the height requirement.
Answer and Explanation:
|
Enter your step-by-step answer and explanations here. |
<i> Women’s pulse rates are normally distributed with a mean of 69.4 beats per minute and a standard deviation of 11.3 beats per minute. What is the z-score for a woman having a pulse rate of 66 beats per minute?
Student’s answer:
Let
Corrections:
|
Enter your corrections and explanations here. |
<b> What is the cumulative area from the left under the curve for a z-score of -0.875? What is the area on the right of that z-score?
Answer and Explanation:
|
Enter your step-by-step answer and explanations here. |
<i> If the area under the standard normal distribution curve is 0.6573 from the right, what is the corresponding z-score?
Student’s answer: We plug in “=NORM.INV(0.6573, 0, 1)” into Excel and get a z-score of 0.41.
Corrections:
|
Enter your corrections and explanations here. |
<p> Manhole covers must be a minimum of 22 in. in diameter, but can be as much as 60 in. Men have shoulder widths that are normally distributed with a mean of 18.2 and a standard deviation of 2.09 in. Assume that a manhole cover is constructed with a diameter of 22.5 in. What percentage of men will fit into a manhole with this diameter?
Student’s answer: We need to find the probability that men will fit into the manhole. The first step is to find the probability that the men’s shoulder is less than 22.5 inches.
Continue the solution:
|
Enter your step-by-step answer and explanations here. |
In: Statistics and Probability
Reba Dixon is a fifth-grade school teacher who earned a salary
of $38,000 in 2020. She is 45 years old and has been divorced for
four years. She receives $1,200 of alimony payments each month from
her former husband (divorced in 2016). Reba also rents out a small
apartment building. This year Reba received $50,000 of rental
payments from tenants and she incurred $19,500 of expenses
associated with the rental.
Reba and her daughter Heather (20 years old at the end of the year)
moved to Georgia in January of this year. Reba provides more than
one-half of Heather’s support. They had been living in Colorado for
the past 15 years, but ever since her divorce, Reba has been
wanting to move back to Georgia to be closer to her family.
Luckily, last December, a teaching position opened up and Reba and
Heather decided to make the move. Reba paid a moving company $2,250
to move their personal belongings, and she and Heather spent two
days driving the 1,600 miles to Georgia.
Reba rented a home in Georgia. Heather decided to continue living
at home with her mom, but she started attending school full time in
January and throughout the rest of the year at a nearby university.
She was awarded a $3,360 partial tuition scholarship this year, and
Reba helped out by paying the remaining $500 tuition cost. If
possible, Reba thought it would be best to claim the education
credit for these expenses.
Reba wasn't sure if she would have enough items to help her benefit
from itemizing on her tax return. However, she kept track of
several expenses this year that she thought might qualify if she
was able to itemize. Reba paid $6,520 in state income taxes and
$14,100 in charitable contributions during the year. She also paid
the following medical-related expenses for herself and Heather:
| Insurance premiums | $ | 8,960 |
| Medical care expenses | $ | 1,100 |
| Prescription medicine | $ | 470 |
| Nonprescription medicine | $ | 100 |
| New contact lenses for Heather | $ | 200 |
Shortly after the move, Reba got distracted while driving and
she ran into a street sign. The accident caused $1,020 in damage to
the car and gave her whiplash. Because the repairs were less than
her insurance deductible, she paid the entire cost of the repairs.
Reba wasn’t able to work for two months after the accident.
Fortunately, she received $2,000 from her disability insurance. Her
employer, the Central Georgia School District, paid 60 percent of
the premiums on the policy as a nontaxable fringe benefit and Reba
paid the remaining 40 percent portion.
A few years ago, Reba acquired several investments with her portion
of the divorce settlement. This year she reported the following
income from her investments: $2,200 of interest income from
corporate bonds and $1,740 interest income from City of Denver
municipal bonds. Overall, Reba’s stock portfolio appreciated by
$13,510, but she did not sell any of her stocks.
Heather reported $6,400 of interest income from corporate bonds she
received as gifts from her father over the last several years. This
was Heather’s only source of income for the year.
Reba had $11,270 of federal income taxes withheld by her employer.
Heather made $1,120 of estimated tax payments during the year. Reba
did not make any estimated payments. Reba had qualifying insurance
for purposes of the Affordable Care Act (ACA).
a. Determine Reba’s federal income taxes due or taxes payable for the current year. Use Tax Rate Schedule for reference. (Do not round intermediate values. Leave no answer blank. Enter zero if applicable.)
2020 Tax Rate Schedules
Individuals
Schedule X-Single
| If taxable income is over: | But not over: | The tax is: |
|---|---|---|
| $ 0 | $ 9,875 | 10% of taxable income |
| $ 9,875 | $ 40,125 | $987.50 plus 12% of the excess over $9,875 |
| $ 40,125 | $ 85,525 | $4,617.50 plus 22% of the excess over $40,125 |
| $ 85,525 | $163,300 | $14,605.50 plus 24% of the excess over $85,525 |
| $163,300 | $207,350 | $33,271.50 plus 32% of the excess over $163,300 |
| $207,350 | $518,400 | $47,367.50 plus 35% of the excess over $207,350 |
| $518,400 | — | $156,235 plus 37% of the excess over $518,400 |
Schedule Y-1-Married Filing Jointly or Qualifying Widow(er)
| If taxable income is over: | But not over: | The tax is: |
|---|---|---|
| $ 0 | $ 19,750 | 10% of taxable income |
| $ 19,750 | $ 80,250 | $1,975 plus 12% of the excess over $19,750 |
| $ 80,250 | $171,050 | $9,235 plus 22% of the excess over $80,250 |
| $171,050 | $326,600 | $29,211 plus 24% of the excess over $171,050 |
| $326,600 | $414,700 | $66,543 plus 32% of the excess over $326,600 |
| $414,700 | $622,050 | $94,735 plus 35% of the excess over $414,700 |
| $622,050 | — | $167,307.50 plus 37% of the excess over $622,050 |
Schedule Z-Head of Household
| If taxable income is over: | But not over: | The tax is: |
|---|---|---|
| $ 0 | $ 14,100 | 10% of taxable income |
| $ 14,100 | $ 53,700 | $1,410 plus 12% of the excess over $14,100 |
| $ 53,700 | $ 85,500 | $6,162 plus 22% of the excess over $53,700 |
| $ 85,500 | $163,300 | $13,158 plus 24% of the excess over $85,500 |
| $163,300 | $207,350 | $31,830 plus 32% of the excess over $163,300 |
| $207,350 | $518,400 | $45,926 plus 35% of the excess over $207,350 |
| $518,400 | — | $154,793.50 plus 37% of the excess over $518,400 |
Schedule Y-2-Married Filing Separately
| If taxable income is over: | But not over: | The tax is: |
|---|---|---|
| $ 0 | $ 9,875 | 10% of taxable income |
| $ 9,875 | $ 40,125 | $987.50 plus 12% of the excess over $9,875 |
| $ 40,125 | $ 85,525 | $4,617.50 plus 22% of the excess over $40,125 |
| $ 85,525 | $163,300 | $14,605.50 plus 24% of the excess over $85,525 |
| $163,300 | $207,350 | $33,271.50 plus 32% of the excess over $163,300 |
| $207,350 | $311,025 | $47,367.50 plus 35% of the excess over $207,350 |
| $311,025 | — | $83,653.75 plus 37% of the excess over $311,025 |
In: Accounting
Kristen, who was active in competitive sports throughout high school, has decided to run a marathon with some of her college friends. She has started training and monitors her miles, time, and calories using a wrist band and training app. She is 25 years old, 5 ft, 8 in. tall, and weighs 135 lb. She eats all sorts of foods, likes fruits and vegetables, but tries to avoid greasy foods. She says coffee is her downfall—she drinks 4–6 cups a day. She doesn't like sweets, although she keeps ice cream in her freezer. A family history notes that her mother needed angioplasty to treat occluded arteries shortly after menopause and that her father is not at risk for any chronic conditions. Although she would eventually like to have children, Kristen is not pregnant now. An analysis of a 24-hour dietary recall shows the following:
2090 cal
352 g carbohydrate (67% of calories)
41 g total fiber
34 mg iron
958 g calcium
690 mcg RAE vitamin A
98 g protein (19% of calories)
33 g fat (14% of calories) (7 g saturated fat, 1 g trans
fat, 1.5 g omega-3 fatty acid, 99 mg cholesterol)
3343 mg sodium
158 mg vitamin C
5.0 mcg vitamin D
8.7 mg TE vitamin E
586 mcg DFE folic acid
283 mg choline
1. How many calories does Kristen need to maintain her weight?
2. Is she eating enough to support daily workouts?
3. Describe three health-promoting aspects of Kristen's
diet?
4. Make three suggestions that could improve Kristen's diet.
In: Nursing
The term “Marketing Myopia” was coined by the late Harvard Business School marketing professor, Theodore Levitt, in a 1960 HBR article (republished in 2004). The “heart of the article,” according to Deighton, a distinguished Harvard Professor, is Levitt’s argument that companies are too focused on producing goods or services and don’t spend enough time understanding what customers want or need. Therefore, he “encouraged executives to switch from a production orientation to a consumer orientation.” As Levitt used to tell his students, “People don’t want a quarter-inch drill. They want a quarter-inch hole!”
“The genius of the original article is that it is so easy to be myopic when it comes to marketing,” says Deighton. “Any marketer is obligated to be concerned with programs, tactics, campaigns, etc. Unfortunately, the clock never stops long enough to answer the question, ‘Why are you doing what you are doing?’ So it’s far too easy to lose sight of the big picture.” The other thing that made the article so significant at the time of its publication is that it reminded CEOs that marketing is part of their job: “[Levitt] tells the leader of the organization: you are in business because you have a customer. Therefore you have to think about marketing,” Deighton explains.
In 2010, Craig Smith at INSEAD, Minette Drumwright at UT Austin, and Mary Gentile at Babson, published a paper criticizing Marketing Myopia. They posited that marketers have taken Levitt’s advice to an extreme, creating a new kind of short sightedness, marked by a single-minded focus on the customer, a narrow definition of the customer, and a failure to address the multiple stakeholders who have arisen out of the “changed societal context of business”. There is no doubt that Levitt believed the entire corporation must be viewed as a customer-creating and customer-satisfying organism, and Deighton admits that this is one of the potential pitfalls of Levitt’s original idea: it “puts great trust in the consumer.” In his original article, Levitt acknowledged how difficult it can be to listen to customers; he wrote: “Consumers are unpredictable, varied, fickle, stupid, shortsighted, stubborn, and generally bothersome.” But Smith, Drumwright, and Gentile go even further, arguing that it’s not just about listening to consumers but about hearing all of the stakeholders who contribute to your company’s success.
In: Finance
In: Anatomy and Physiology
3.Problem 3
The Business Graduate School at RUM is studying the test scores from this year's candidates. In particular, we are interested to know if the there is a dependent relationship between the candidates' verbal and quantitative scores.
| Quantitative Scores | |||
| Low | High | ||
| Verbal Scores | Low | 39 | 155 |
| High | 22 | 170 | |
Use an alpha = 0.025.
What is the critical value for this test?
Select one:
a. 11.14
b. 7.38
c. 3.84
d. 5.02
I just need the answer
In: Statistics and Probability
Retaking the SAT: Many high school students take the SAT's twice; once in their Junior year and once in their Senior year. In a sample of 50 such students, the score on the second try was, on average, 28 points above the first try with a standard deviation of 13 points. Test the claim that retaking the SAT increases the score on average by more than 25 points. Test this claim at the 0.01 significance level.
(a) The claim is that the mean difference is greater than 25 (μd > 25), what type of test is this?
This is a two-tailed test.
This is a left-tailed test.
This is a right-tailed test.
(b) What is the test statistic? Round your answer to 2 decimal places.
(c) Use software to get the P-value of the test statistic. Round to 4 decimal places.
(d) What is the conclusion regarding the null hypothesis?
reject H0
fail to reject H0
(e) Choose the appropriate concluding statement.
The data supports the claim that retaking the SAT increases the score on average by more than 25 points.
There is not enough data to support the claim that retaking the SAT increases the score on average by more than 25 points.
We reject the claim that retaking the SAT increases the score on average by more than 25 points.
We have proven that retaking the SAT increases the score on average by more than 25 points.
In: Statistics and Probability
How do California high school students compare to students nationwide in their college readiness, as measured by their SAT scores? The national average scores for the class of 2017 were 533 on Evidence-Based Reading and Writing and 527 on the math portion.† Suppose that 100 California students from the class of 2017 were randomly selected and their SAT scores were recorded in the following table.
|
Evidence-Based Reading and Writing |
Math | |
|---|---|---|
| Sample Average | 529 | 521 |
| Sample Standard Deviation | 96 | 99 |
(a)
Do the data provide sufficient evidence to indicate that the average Evidence-Based Reading and Writing score for all California students in the class of 2017 differs from the national average? Use α = 0.05.
State the null and alternative hypotheses.
H0: μ < 527 versus Ha: μ > 527
H0: μ = 533 versus Ha: μ > 533
H0: μ = 533 versus Ha: μ ≠ 533
H0: μ = 533 versus Ha: μ < 533
H0: μ ≠ 527 versus Ha: μ = 527
Find the test statistic and the p-value. (Round your test statistic to two decimal places and your p-value to four decimal places.)
z=
p-value =
State your conclusion.
The p-value is less than alpha, so H0 is rejected. There is sufficient evidence to indicate that the average Evidence-Based Reading and Writing score for all California students in the class of 2017 is different from the national average.
The p-value is greater than alpha, so H0 is not rejected. There is sufficient evidence to indicate that the average Evidence-Based Reading and Writing score for all California students in the class of 2017 is different from the national average.
The p-value is greater than alpha, so H0 is not rejected. There is insufficient evidence to indicate that the average Evidence-Based Reading and Writing score for all California students in the class of 2017 is different from the national average.
The p-value is less than alpha, so H0 is rejected. There is insufficient evidence to indicate that the average Evidence-Based Reading and Writing score for all California students in the class of 2017 is different from the national average.
(b)
Do the data provide sufficient evidence to indicate that the average math score for all California students in the class of 2017 is different from the national average? Use α = 0.05.
State the null and alternative hypotheses.
H0: μ < 527 versus Ha: μ > 527
H0: μ = 533 versus Ha: μ > 533
H0: μ ≠ 527 versus Ha: μ = 527
H0: μ = 533 versus Ha: μ < 533
H0: μ = 527 versus Ha: μ ≠ 527
Find the test statistic and the p-value. (Round your test statistic to two decimal places and your p-value to four decimal places.)
z=
p-value =
State your conclusion.
The p-value is greater than alpha, so H0 is not rejected. There is insufficient evidence to indicate that the average math score for all California students in the class of 2017 is different from the national average.
The p-value is less than alpha, so H0 is rejected. There is sufficient evidence to indicate that the average math score for all California students in the class of 2017 is different from the national average.
The p-value is greater than alpha, so H0 is not rejected. There is sufficient evidence to indicate that the average math score for all California students in the class of 2017 is different from the national average.
The p-value is less than alpha, so H0 is rejected. There is insufficient evidence to indicate that the average math score for all California students in the class of 2017 is different from the national average.
In: Statistics and Probability