For the data set below, calculate r, r 2, and a 95% confidence interval in r units. Then write a one- to two-sentence conclusion statement that includes whether the null hypothesis was rejected or not. Assume a two-tailed hypothesis and α = .05.
|
Case 1 |
Case 2 |
Case 3 |
Case 4 |
Case 5 |
Case 6 |
|
|
X |
1.05 |
1.15 |
1.30 |
2.00 |
1.75 |
1.00 |
|
Y |
2 |
2 |
3 |
4 |
5 |
2 |
In: Statistics and Probability
Solve by using python function. use loop
Input; Crossing Times = { 10,15,20,25}
1.Firstly person '1' and '2' cross the path with total time about 15 min(maximum of 10, 15)
2.Now the person '1' will come back with total time of '10' minutes.
3. Now, person 1 and person 3 cross the path with total of about 20 minutes .(maximum of 10,20)
4. Now the person 1 will come back in 10 mintues
5. Lastly person 1 and person 4 will cross the path together in about 25 minutes(max of 10,25)
print the total sum of all(15+10+20+10+25)
In: Computer Science
|
W |
1 |
2 |
3 |
4 |
|
Pr(W=i|F=1) |
0.2 |
0.3 |
0.3 |
0.2 |
|
W |
1 |
2 |
3 |
4 |
|
Pr(W=i|F=0) |
0.1 |
0.35 |
0.4 |
0.15 |
Suppose there are 20 fertilized tomato plots and 20 unfertilized tomato plots in the field,
In: Economics
Consider the three following pieces of pseudocodes. In each case,
- Give the number of times "Hello" will be printed,
- Generalize, giving the number of times as a function of n
- Express this in theta notation in terms of n.
a) set n = 32
set i = 1
while i<= n
print "Hello"
i=i*2
endwhile
b) set n = 4
set i = 1
while i not equal to n
print "Hello"
i=i+2
endwhile
c) set n = 4
set i = 1
while i<= n
set j = 1
while j <= i
print "Hello"
j=j+1
endwhile
i=i+1
endwhile
In: Computer Science
Each of the four independent situations below describes a sales-type lease in which annual lease payments of $145,000 are payable at the beginning of each year. Each is a finance lease for the lessee. (FV of $1, PV of $1, FVA of $1, PVA of $1, FVAD of $1 and PVAD of $1) (Use appropriate factor(s) from the tables provided.)
| Situation | ||||||
| 1 | 2 | 3 | 4 | |||
| Lease term (years) | 6 | 6 | 7 | 7 | ||
| Lessor's and lessee's interest rate | 11% | 10% | 12% | 12% | ||
| Residual value: | ||||||
| Estimated fair value | 0 | $59,000 | $8,900 | $59,000 | ||
| Guaranteed by lessee | 0 | 0 | $8,900 | $69,000 | ||
Determine the following amounts at the beginning of the lease:
(Round your intermediate and final answer to the nearest
whole dollar amount.)
| Situation | |||||
| 1 | 2 | 3 | 4 | ||
| A | The lessor's | ||||
| 1. Total lease payments | 870,000 | 870,000 | 1,015,000 | ||
| 2. Gross investment in the lease | 870,000 | 929,000 | |||
| 3. Net investment in the lease | 680,906 | ||||
| B. | The lessee's | ||||
| 4. Total lease payments | 870,000 | 870,000 | 1,015,000 | 1,025,000 | |
| 5. Right-of-use asset | 680,906 | 694,665 | 741,155 | ||
| 6. Lease liability | 680,906 | 694,665 | 741,155 | ||
In: Accounting
1. Ph of H3O+ of 5.7x10^3
2. Ph of a 1.5x10^-2 m for HBr
3. ph of 3.24x10^-4 m of hypochlorous acid ka2.9x10^-8
In: Chemistry
When an automobile is stopped by a roving safety patrol, each tire is checked for tire wear, and each headlight is checked to see whether it is properly aimed. Let X denote the number of headlights that need adjustment, and let Y denote the number of defective tires.
(a) If X and Y are independent with pX(0) = 0.5, pX(1) = 0.3, pX(2) = 0.2, and pY(0) = 0.1, pY(1) = 0.2, pY(2) = pY(3) = 0.05, pY(4) = 0.6, display the joint pmf of (X, Y) in a joint probability table.
| y | ||||||
|
p(x, y) |
0 | 1 | 2 | 3 | 4 | |
| x | 0 | |||||
| 1 | ||||||
| 2 | ||||||
(b) Compute P(X ≤ 1 and Y ≤ 1) from the
joint probability table.
P(X ≤ 1 and Y ≤ 1) =
Does P(X ≤ 1 and Y ≤ 1) equal the
product P(X ≤ 1) · P(Y ≤
1)?
YesNo
(c) What is P(X + Y = 0) (the
probability of no violations)?
P(X + Y = 0) =
(d) Compute P(X + Y ≤ 1).
P(X + Y ≤ 1) =
In: Math
Two independent methods of forecasting based on judgment and
experience have been prepared each month for the past 10 months.
The forecasts and actual sales are as follows:
| Month | Sales | Forecast 1 | Forecast 2 |
| 1 | 845 | 815 | 820 |
| 2 | 835 | 835 | 825 |
| 3 | 795 | 820 | 825 |
| 4 | 820 | 830 | 795 |
| 5 | 795 | 785 | 780 |
| 6 | 835 | 785 | 771 |
| 7 | 805 | 810 | 785 |
| 8 | 850 | 780 | 785 |
| 9 | 840 | 805 | 830 |
| 10 | 805 | 815 | 825 |
a. Compute the MSE and MAD for each forecast.
(Round your answers to 2 decimal
places.)
| MSE | MAD | |
| Forecast 1 | ? | ? |
| Forecast 2 | ? | ? |
b. Compute MAPE for each forecast.
(Round your intermediate calculations to 5 decimal places
and final answers to 4 decimal places.)
| MAPE F1 | ? % |
| MAPE F2 | ? % |
c. Prepare a naive forecast for periods 2
through 11 using the given sales data. Compute each of the
following; (1) MSE, (2) MAD, (3) tracking signal at month 10, and
(4) 2s control limits. (Round your answers to 2
decimal places.)
| MSE | ? |
| MAD | ? |
| Tracking signal | ? |
| Control limits | 0 ± ? |
In: Advanced Math
Two independent methods of forecasting based on judgment and
experience have been prepared each month for the past 10 months.
The forecasts and actual sales are as follows:
| Month | Sales | Forecast 1 | Forecast 2 |
| 1 | 845 | 815 | 820 |
| 2 | 835 | 835 | 825 |
| 3 | 795 | 820 | 825 |
| 4 | 820 | 830 | 795 |
| 5 | 795 | 785 | 780 |
| 6 | 835 | 785 | 771 |
| 7 | 805 | 810 | 785 |
| 8 | 850 | 780 | 785 |
| 9 | 840 | 805 | 830 |
| 10 | 805 | 815 | 825 |
a. Compute the MSE and MAD for each forecast.
(Round your answers to 2 decimal
places.)
| MSE | MAD | |
| Forecast 1 | ? | ? |
| Forecast 2 | ? | ? |
b. Compute MAPE for each forecast.
(Round your intermediate calculations to 5 decimal places
and final answers to 4 decimal places.)
| MAPE F1 | ? % |
| MAPE F2 | ? % |
c. Prepare a naive forecast for periods 2
through 11 using the given sales data. Compute each of the
following; (1) MSE, (2) MAD, (3) tracking signal at month 10, and
(4) 2s control limits. (Round your answers to 2
decimal places.)
| MSE | ? |
| MAD | ? |
| Tracking signal | ? |
| Control limits | 0 ± ? |
In: Math