Questions
Carry out a one-way ANOVA by hand to test the following research question: Carl wants to...

Carry out a one-way ANOVA by hand to test the following research question: Carl wants to know if drinking beer (2, 5 or 8 beers) affects the number of times people sing karaoke  at a local bar in a given night. He is predicting that the groups will differ significantly (α = .05). (Perform post-hoc tests if necessary)

2 beers

5 beers

8 beers

1

2

4

2

1

3

1

3

5

3

2

2

In: Statistics and Probability

Fallacies Part II 1. Hasty Generalisation Fallacies Part III 1. Ad Hominem 2. Appeal to force...

Fallacies Part II

1. Hasty Generalisation

Fallacies Part III

1. Ad Hominem
2. Appeal to force
3. False Dilemma

Fallacies Part IV

1. Appeal to pity
2. Popular Appeal
3. Inappropriate Appeal to Authority
4. Slippery Slope
5. Questionable Cause

In: Economics

A study was designed to compare the attitudes of two groups of nursing students towards computers....

A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken a statistical methods course that involved significant computer interaction. Group 2 had taken a statistic methods course that did not use computers. The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 10 nursing students from Group 1 resulted in a mean score of 55.9 with a standard deviation of 5.4. A random sample of 14 nursing students from Group 2 resulted in a mean score of 64.5 with a standard deviation of 5.7. Can you conclude that the mean score for Group 1 is significantly lower than the mean score for Group 2? Let μ1 represent the mean score for Group 1 and μ2 represent the mean score for Group 2. Use a significance level of α=0.05 for the test. Assume that the population variances are equal and that the two populations are normally distributed. Step 2 of 4 : Compute the value of the t test statistic. Round your answer to three decimal places. Step 3 of 4: Determine the decision rule for rejecting the null hypothesis H0. Round your answer to three decimal places. Step 4 of 4: State the test's conclusion. A. Reject Null Hypothesis B. Fail to Reject Null Hypothesis

In: Statistics and Probability

in animal cells and in the meristem cells of land plants, the nuclear envelope disintegrates during...

in animal cells and in the meristem cells of land plants, the nuclear envelope disintegrates during mitosis. This disintegration does occur in the cells of most protists. According to our current knowledge of plant evolution, which group of organism should show mitosis most similar to land plants?

A) red algae

B) unicellular chlorophytes

C) charophytes

D) multicellular chlorophytes

12) The earliest land plants faced many challenges when they first tried to survive on land, however ____ was most definitely not one of them.

A) dessication

B) obtaining adequate light

C) sperm transfer

D) animal predation

13) working from deep geologic strata toward shallow strata, what is the sequence in which fossils of these groups should make their appearance?

1) charophytes

2) single celled chlorphytes

3) bryophytes

4) plants with a dominant sporophytes

A) 1 -3 -2 -4

B) 2-1-3-4

C) 3-2-4-1

D) 2-4-1-3

14. you are a botanist studying a new plant species discovered in the hot and dry American southwest which adaptation is the least useful for such a plant that endures water shorages?

A) Mycorrhizae associated with root systems.

B) the ability to close the stomata during the hottest part of the day

C) A thick waxy cuticle on the epidermis

D) The development of large leaf surfaces.

15. you find a plant growing in a dense forest, what adaptation would be most useful for the plant to obtain adequate light exposure?

A) flower

B) lack of petioles

C) apical dominance

D) Lateral buds.

In: Biology

Consider the data in the table collected from four independent populations. The conclusion of a​ one-way...

Consider the data in the table collected from four independent populations. The conclusion of a​ one-way ANOVA test using

alphaαequals=0.05

is that the population means are not all the same. Determine which means are different using

alphaαequals=0.05

Sample

1

Sample

2

Sample

3

Sample

4

6

13

23

9

7

16

13

8

8

19

19

10

9

22

Click here to view the ANOVA summary table.

LOADING...

Click here to view a table of critical values for the studentized range.

LOADING...

Let

x overbarx1​,

x overbarx2​,

x overbarx3​,

and

x overbarx4

be the means for samples​ 1, 2,​ 3, and​ 4, respectively. Find the absolute values of the differences between the means.

StartAbsoluteValue x overbar 1 minus x overbar 2 EndAbsoluteValuex1−x2

equals=

nothing

StartAbsoluteValue x overbar 2 minus x overbar 3 EndAbsoluteValuex2−x3

equals=

nothing

StartAbsoluteValue x overbar 1 minus x overbar 3 EndAbsoluteValuex1−x3

equals=

nothing

StartAbsoluteValue x overbar 2 minus x overbar 4 EndAbsoluteValuex2−x4

equals=

nothing

StartAbsoluteValue x overbar 1 minus x overbar 4 EndAbsoluteValuex1−x4

equals=

nothing

StartAbsoluteValue x overbar 3 minus x overbar 4 EndAbsoluteValuex3−x4

equals=

nothing

​(Type integers or decimals. Do not​ round.)

Source

Sum of Squares

Degrees of Freedom

Mean Sum of Squares

F

Between

352.25

3

117.417

13.693

Within

85.75

10

8.575

Total

438

13

In: Statistics and Probability

Consider the piston ring data in the following table. Assume that specifications are 74.00 ± 0.035...

Consider the piston ring data in the following table. Assume that specifications are 74.00 ± 0.035 mm. Estimate the process capability (Cp and Cpk) using:

  1. Sample Range Measurements
  2. Sample Std Dev. Measurements

Convert the Cp found above into approximate dpm.

Inside Diameter Measurements (mm) for Automobile Piston Rings

Sample

ID

1

74.03

1

74.002

1

74.019

1

73.992

1

74.008

2

73.995

2

73.992

2

74.001

2

74.011

2

74.004

3

73.988

3

74.024

3

74.021

3

74.005

3

74.002

4

74.002

4

73.996

4

73.993

4

74.015

4

74.009

5

73.992

5

74.007

5

74.015

5

73.989

5

74.014

6

74.009

6

73.994

6

73.997

6

73.985

6

73.993

7

73.995

7

74.006

7

73.994

7

74

7

74.005

8

73.985

8

74.003

8

73.993

8

74.015

8

73.988

9

74.008

9

73.995

9

74.009

9

74.005

9

74.004

10

73.998

10

74

10

73.99

10

74.007

10

73.995

11

73.994

11

73.998

11

73.994

11

73.995

11

73.99

12

74.004

12

74

12

74.007

12

74

12

73.996

13

73.983

13

74.002

13

73.998

13

73.997

13

74.012

14

74.006

14

73.967

14

73.994

14

74

14

73.984

15

74.012

15

74.014

15

73.998

15

73.999

15

74.007

In: Statistics and Probability

A machine costing $213,200 with a four-year life and an estimated $16,000 salvage value is installed...

A machine costing $213,200 with a four-year life and an estimated $16,000 salvage value is installed in Luther Company’s factory on January 1. The factory manager estimates the machine will produce 493,000 units of product during its life. It actually produces the following units: 122,600 in Year 1, 122,500 in Year 2, 120,100 in Year 3, 137,800 in Year 4. The total number of units produced by the end of Year 4 exceeds the original estimate—this difference was not predicted. (The machine cannot be depreciated below its estimated salvage value.)

Required:

Compute depreciation for each year (and total depreciation of all years combined) for the machine under each depreciation method. (Round your per unit depreciation to 2 decimal places. Round your answers to the nearest whole dollar.)

Compute depreciation for each year (and total depreciation of all years combined) for the machine under the Straight-line depreciation.

Straight-Line Depreciation
Year Depreciation Expense
1
2
3
4
Total $0

Compute depreciation for each year (and total depreciation of all years combined) for the machine under the Units of production.

Units of Production
Year Units Depreciable Units Depreciation per unit Depreciation Expense
1 122,600
2 122,500
3 120,100
4 137,800
Total $0

Compute depreciation for each year (and total depreciation of all years combined) for the machine under the Double-declining-balance.

DDB Depreciation for the Period End of Period
Year Beginning of Period Book Value Depreciation Rate Depreciation Expense Accumulated Depreciation Book Value
1 % $0
2 % 0
3 % 0
4 % 0
Total $0

In: Accounting

1) At which point along the titration curve of a weak acid titrated with a strong...

1) At which point along the titration curve of a weak acid titrated with a strong base does the pH = pKa

- At the half equivalence volume

- At the equilavence volume

- Before any base is added

- Beyond equilavence volume

2) In a titration of a 100.0mL 1.00M HA weak acid solution with 1.00M NaOH, what is the pH of the solution after the addition of 131 mL of NaOH?   Ka = 1.80 x 10-5 for HA. (3 significant figures)

**Remember to calculate the equivalence volume and think about in which region along the titration curve the volume of base falls, region 1, 2, 3, or 4**

3)In a titration of a 100.0mL 1.00M HCl strong acid solution with 1.00M NaOH, what is the pH of the solution after the addition of 121 mL of NaOH? (3 significant figures)

**Remember to calculate the equivalence volume and think about in which region along the titration curve the volume of base falls, region 1, 2, 3, or 4**

4) In a titration of a 100.0mL 1.00M HA weak acid solution with 1.00M NaOH, what is the pH of the solution after the addition of 49.5 mL of NaOH? Ka = 1.80 x 10-5 for HA. (3 significant figures)

**Remember to calculate the equivalence volume and think about in which region along the titration curve the volume of base falls, region 1, 2, 3, or 4**

5) In a titration of a 100.0mL 1.00M HCl strong acid solution with 1.00M NaOH, what is the pH of the solution after the addition of 30.9 mL of NaOH? (3 significant figures)

**Remember to calculate the equivalence volume and think about in which region along the titration curve the volume of base falls, region 1, 2, 3, or 4**

In: Chemistry

A machine costing $257,500 with a four-year life and an estimated $20,000 salvage value is installed...

A machine costing $257,500 with a four-year life and an estimated $20,000 salvage value is installed in Luther Company’s factory on January 1. The factory manager estimates the machine will produce 475,000 units of product during its life. It actually produces the following units: 220,000 in Year 1, 124,600 in Year 2, 121,800 in Year 3, and 15,200 in Year 4. The total number of units produced by the end of Year 4 exceeds the original estimate—this difference was not predicted. (The machine cannot be depreciated below its estimated salvage value.)
Required:
Compute depreciation for each year (and total depreciation of all years combined) for the machine under each depreciation method. (Round your per unit depreciation to 2 decimal places.)
Complete this question by entering your answers in the tabs below.

Compute depreciation for each year (and total depreciation of all years combined) for the machine under the Straight-line depreciation.

Straight-Line Depreciation
Year Depreciation Expense
1
2
3
4
Total

Compute depreciation for each year (and total depreciation of all years combined) for the machine under the Units of production.

Units of Production
Year Units Depreciable Units Depreciation per unit Depreciation Expense
1 220,000
2 124,600
3 121,800
4 15,200
Total

Compute depreciation for each year (and total depreciation of all years combined) for the machine under the Double-declining-balance.

DDB Depreciation for the Period End of Period
Year Beginning of Period Book Value Depreciation Rate Depreciation Expense Accumulated Depreciation Book Value
1 %
2 %
3 %
4 %
Total

In: Accounting

Given a $250 annual deductible, a $5,000 lid on the co-insurance, 80/20 co-insurance, and a $250,000...

Given a $250 annual deductible, a $5,000 lid on the co-insurance, 80/20 co-insurance, and a $250,000 policy limit, how much of a $27,500 medical bill will be paid by the insured?

Question 11 options:

1)

$ 250

2)

$5,000

3)

$5,450

4)

$5,250

5)

$5,700

Question 12 (0.5 points)

Disability income policies usually have ____ that is a time delay from the date of the issuance of the policy until benefit privileges are activated.

Question 12 options:

1)

waiting periods

2)

probationary periods

3)

elimination periods

4)

internal limit periods

5)

outer limits

Question 13 (0.5 points)

If your employment is terminated, COBRA provides for:

Question 13 options:

1)

cancellation of all group insurance benefits.

2)

continuation of group insurance benefits until you are reemployed.

3)

permanent continuation of group health insurance.

4)

temporary continuation of group insurance benefits; you pay premiums.

5)

temporary continuation of group insurance benefits; employer pays premiums.

Question 14 (0.5 points)

Auto insurance is needed primarily because of:

Question 14 options:

1)

potential damage to auto.

2)

potential liability claims.

3)

lender's requirements.

4)

state law.

5)

federal requirements.

Question 15 (0.5 points)

All of the following except a ____ are highly recommended for a long-term disability income policy.

Question 15 options:

1)

guaranteed renewable clause

2)

cost-of-living adjustment

3)

long duration of benefit

4)

short waiting period

5)

waiver of premium

In: Accounting