Raner, Harris & Chan is a consulting firm that specializes in information systems for medical and dental clinics. The firm has two offices—one in Chicago and one in Minneapolis. The firm classifies the direct costs of consulting jobs as variable costs. A contribution format segmented income statement for the company’s most recent year is given:

Assume that Minneapolis’ sales by major market are:

The company would like to initiate an intensive advertising campaign in one of the two market segments during the next month. The campaign would cost $10,000. Marketing studies indicate that such a campaign would increase sales in the Medical market by $87,500 or increase sales in the Dental market by $75,000.

Required:

1. How much would the company's profits increase (decrease) if it implemented the advertising campaign in the Medical Market?

2. How much would the company's profits increase (decrease) if it implemented the advertising campaign in the Dental Market?

3. In which of the markets would you recommend that the company focus its advertising campaign?

Exercise 6-17 Working with a Segmented Income Statement [LO6-4]

Raner, Harris & Chan is a consulting firm that specializes in information systems for medical and dental clinics. The firm has two offices—one in Chicago and one in Minneapolis. The firm classifies the direct costs of consulting jobs as variable costs. A contribution format segmented income statement for the company’s most recent year is given:

Assume that Minneapolis’ sales by major market are:

The company would like to initiate an intensive advertising campaign in one of the two market segments during the next month. The campaign would cost $11,600. Marketing studies indicate that such a campaign would increase sales in the Medical market by $101,500 or increase sales in the Dental market by $87,000.

Required:

1. How much would the company's profits increase (decrease) if it implemented the advertising campaign in the Medical Market?

2. How much would the company's profits increase (decrease) if it implemented the advertising campaign in the Dental Market?

3. In which of the markets would you recommend that the company focus its advertising campaign?

Consider the following time series data:

Month 1 2 3 4 5 6 7

Value 23 15 20 12 18 22 15

complete java binary search tree

/*
* Complete the printInLevelOrder() method
* Complete the visuallyIdentical(A4BST rhs) method
* No other methods/variables should be added/modified
*/
public class A4BST<E extends Comparable<? super E>> {
   /*
   * Grading:
   * Correctly prints values in level order - 1.5pt
   * Runs in O(N) - 1.5pt
   */
   public String printInLevelOrder()
   {
       String content = "";
       /*
       * Add items from the tree to content one level at a time
       * No line breaks are required between levels
       * Ensure method runs in O(N) - does not revisit any node
       */
       return content;
   }
   /*
   * Grading:
   * Correctly compares the structure of both trees - 3pts
   */
   public boolean visuallyIdentical(A4BST rhs)
   {
       /*
       * Check if the structure of the local tree and the rhs tree are identical
       * This means they have the same left/right connections
       * This means there are no extra connections in either tree
       * The values at each position do not need to match, only the structure of the tree
       * Think about if you drew both trees on paper, would they visually look the same (besides values)
       */
       return false;
   }
  
   private Node root;

   public A4BST()
   {
       root = null;
   }

   public String printTree()
   {
       return printTree(root);
   }
   private String printTree(Node current)
   {
       String content = "";
       if(current != null)
       {
           content += "Current:"+current.data.toString();
           if(current.left != null)
           {
               content += "; Left side:"+current.left.data.toString();
           }
           if(current.right != null)
           {
               content += "; Right side:"+current.right.data.toString();
           }
           content+="\n";
           content+=printTree(current.left);
           content+=printTree(current.right);

       }
       return content;
   }
   public String printInOrder()
   {
       return printInOrder(root);
   }
   private String printInOrder(Node current)
   {
       String content = "";
       if(current != null)
       {
           content += printInOrder(current.left);
           content += current.data.toString()+",";
           content += printInOrder(current.right);
       }
       return content;
   }
   public boolean contains(E val)
   {
       Node result = findNode(val, root);

       if(result != null)
           return true;
       else
           return false;
   }
   private Node findNode(E val, Node current)
   {
       //base cases
       if(current == null)
           return null;
       if(current.data.equals(val))
           return current;

       //recursive cases
       int result = current.data.compareTo(val);
       if(result < 0)
           return findNode(val, current.right);
       else
           return findNode(val, current.left);
   }
   public E findMin()
   {
       Node result = findMin(root);
       if(result == null)
           return null;
       else
           return result.data;
   }
   private Node findMin(Node current)//used in findMin and delete
   {
       while(current.left != null)
       {
           current = current.left;
       }
       return current;
   }
   public E findMax()
   {
       Node current = root;
       while(current.right != null)
       {
           current = current.right;
       }
       return current.data;
   }
   public void insert(E val)
   {
       root = insertHelper(val, root);
   }
   public Node insertHelper(E val, Node current)
   {
       if(current == null)
       {
           return new Node(val);
       }
       int result = current.data.compareTo(val);
       if(result < 0)
       {
           current.right = insertHelper(val, current.right);
       }
       else if(result > 0)
       {
           current.left = insertHelper(val, current.left);
       }
       else//update
       {
           current.data = val;
       }
       return current;
   }
   public void remove(E val)
   {
       root = removeHelper(val, root);
   }
   private Node removeHelper(E val, Node current)
   {
       if(current.data.equals(val))
       {
           if(current.left == null && current.right == null)//no children
           {
               return null;
           }
           else if(current.left != null && current.right != null)//two children
           {
               Node result = findMin(current.right);
               result.right = removeHelper(result.data, current.right);
               result.left = current.left;
               return result;
           }
           else//one child
           {
               return (current.left != null)? current.left : current.right;
           }
       }
       int result = current.data.compareTo(val);
       if(result < 0)
       {
           current.right = removeHelper(val, current.right);
       }
       else if(result > 0)
       {
           current.left = removeHelper(val, current.left);
       }
       return current;
   }

   private class Node
   {
       E data;
       Node left, right;
       public Node(E d)
       {
           data = d;
           left = null;
           right = null;
       }
   }

}

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public class A4Driver {

   public static void main(String[] args) {
       A4BST<Integer> tree1 = new A4BST<>();
       tree1.insert(5);
       tree1.insert(3);
       tree1.insert(1);
       tree1.insert(2);
       tree1.insert(9);
       tree1.insert(10);
       tree1.insert(25);
       A4BST<Integer> tree2 = new A4BST<>();
       tree2.insert(8);
       tree2.insert(5);
       tree2.insert(1);
       tree2.insert(3);
       tree2.insert(15);
       tree2.insert(20);
       tree2.insert(25);
       A4BST<Integer> tree3 = new A4BST<>();
       tree3.insert(1);
       tree3.insert(2);
       tree3.insert(3);
       tree3.insert(5);
       tree3.insert(9);
       tree3.insert(10);
       tree3.insert(25);
       System.out.println(tree1.printInLevelOrder());//5, 3, 9, 1, 10, 2, 25
       System.out.println(tree2.printInLevelOrder());//8, 5, 15, 1, 20, 3, 25
       System.out.println(tree3.printInLevelOrder());//1, 2, 3, 4, 5, 9, 10, 25
       System.out.println(tree1.visuallyIdentical(tree2));//true
       System.out.println(tree1.visuallyIdentical(tree3));//false
  
  

   }

}

A student is interested in the sleep quality of students. That student selects a random sample of 21 students (age 19-24 years) from each four undergraduate years (Freshman, Sophomore, Junior and Senior), and applies Pittsburgh Sleep Quality Index (PSQI) and obtains their responses. PSQI includes 19 self-reported items and is designed to evaluate overall sleep quality (Data are presented in Table 1 below). The student is interested in determining whether there is any evidence of a difference in sleep quality across the groups of students representing each of the four different years.

1. What type of analysis should be used to answer this question? Your options are: one sample t-test, one sample z-test, Two sample t-test, chi-square, ANOVA, and paired t-test.
2. Why did you choose that type of analysis?
3. Check if the conditions for reliable use of the test are met.
4. Does the data support the hypothesis that undergraduate years are related to sleep quality PSQI score? Show any output/ graph/ chart used to answer the question.
5. Interpret your findings in context. Describe your findings as if you are interpreting it to a lay person (a person not familiar with hypothesis testing).

Assume a computer with a cache that holds 64 bytes and has a block size of 32 bytes. Direct address mapping is used and from the beginning the cache is empty. The following program sequence is executed:

for (col = 0; col < 2; col++) {

for (row = 0; row < 4; row++)

A[row][col] = B[row] * C[col]; }

Assume that for the variables row and col registers are used.
The matrix A consists of 4 rows and 4 columns with integers (one word long). A is located in the RAM with start address 0 and is stored in rows (A [0] [0], A [0] [1], ... ).
Array B consists of 4 integers (one word long). B is located in RAM with start address 64.
The arrayC consists of 4 integers (one word long). C is located in RAM with start address 80.
What will be the hit probability for the program sequence? What will be the hit probability if 2-way set associative address mapping (with LRU when changing blocks) is used instead of direct address mapping? Also write explanations of how the calculations are done and interpret the results. (Note that the outer loop runs twice and the inner one four times. There will be a total of 24 memory references.)

A 40-year-old male meter technician had just completed a seven-week basic lineman training course. He worked as a meter technician during normal working hours and as a line during unplanned outages. One evening, he was called to repair a power outage at your company. By the time he arrived at the site of the outage, he had already worked two hours of overtime and worked 14 straight hours the day before. At the site, a tree limb had fallen across an overhead power line. The neutral wire in the line was severed and the two energized 120-volt wires were disconnected. The worker removed the tree limb and climbed up a power pole to reconnect the three wires. He was wearing insulated gloves, a hard hat, and safety glasses. He prepared the wires to be connected. While handling the wires, one of the energised wires caught the cuff of his left glove and pulled the cuff down. The conductor contacted the victim's forearm near the wrist. He was electrocuted and fell backwards. Paramedics arrived five minutes after the contact. Firefighters lowered his dead body 30 minutes later. Based on the report, it is vital that this kind of accident should never have happened again. The upper management wants you to create based on the incident that happened, formulate a 10 Step Safety Operating Procedure (SOP) that can cover the element of hazard and mistakes being done. The SOP should have their own justification on why it is needed.

For all the baseball fans out there: Assuming that two teams are evenly matched in the World Series (a championship series of at most 7 games; the first team to win 4 games wins the Series) so that the probability of each team winning each game is 50%, and assuming each game is independent of each other game, what is the probability that the Series will be won in exactly 4 games? 5? 6? that the Series goes to game 7?

Determine the overall heat transfer coefficient (U) in a heat exchanger that uses steam to heat water to the point of vaporization (in vacuum.) The system is non-insulated, so the heat lost to the surroundings must be taken into consideration. While I know that the heat Q = mCdT and the heat transfer rate q = UAdT(Log-mean), I am struggling to equate the two due to the heat lost to the surroundings. How do I go about determining the overall heat transfer coefficient in a system like this?