It is known that a certain basketball player will successfully make a free throw 87.4% of the time. Suppose that the basketball player attempts to make 14 free throws. What is the probability that the basketball player will make at least 11 free throws?
Let XX be the random variable which denotes the number of free throws that are made by the basketball player. Find the expected value and standard deviation of the random variable.
E(X)=
σ=
Suppose that you randomly draw one card from a standard deck of 52 cards. After writing down which card was drawn, you replace the card, and draw another card. You repeat this process until you have drawn 16 cards in all. What is the probability of drawing at least 7 spades?
For the experiment above, let XX denote the number of spades that are drawn. For this random variable, find its expected value and standard deviation.
E(X)=
σ=
In: Statistics and Probability
1. The government of Philippines is proposing a new program to encourage banana farmers to reduce their use of chemicals. Let us assume the present cost of the program as 1,000,000 pesos per participant. The benefits of the program are the reduction in environmental cost estimated at a present value of 4, 000, 000 pesos per participant.
However, the number of farmers that will participate in the program is not known with certainty, and the success of the program in reducing environmental cost is also uncertain.
The following table provides 5 scenarios of a number of participants and the probability of achieving the benefits from reducing environmental cost.
|
Scenario |
Program participants |
% probability of reducing environmental cost |
|
A |
15,000 |
30 |
|
B |
18,000 |
25 |
|
C |
20,000 |
20 |
|
D |
22,000 |
15 |
a) Use the scenario approach of sensitivity analysis to estimate the NPV
b) Under which scenarios will the project be feasible?
c) What advice will you give to the government of Philippines on the feasibility of the project?
In: Economics
In the 1992 presidential election, Alaska's 40 election
districts averaged 1845 votes per district for President Clinton.
The standard deviation was 562. (There are only 40 election
districts in Alaska.) The distribution of the votes per district
for President Clinton was bell-shaped. Let X = number of votes for
President Clinton for an election district. (Source: The World
Almanac and Book of Facts) Round all answers except part e. to 4
decimal places.
a. What is the distribution of X? X ~ N(,)
b. Is 1845 a population mean or a sample mean? Select an answer
Population Mean Sample Mean
c. Find the probability that a randomly selected district had fewer
than 1894 votes for President Clinton.
d. Find the probability that a randomly selected district had
between 1872 and 2162 votes for President Clinton.
e. Find the first quartile for votes for President Clinton. Round
your answer to the nearest whole number.
In: Statistics and Probability
In the 1992 presidential election, Alaska's 40 election
districts averaged 1982 votes per district for President Clinton.
The standard deviation was 578. (There are only 40 election
districts in Alaska.) The distribution of the votes per district
for President Clinton was bell-shaped. Let X = number of votes for
President Clinton for an election district. (Source: The World
Almanac and Book of Facts) Round all answers except part e. to 4
decimal places.
a. What is the distribution of X? X ~ N(,)
b. Is 1982 a population mean or a sample mean? Select an answer
Population Mean Sample Mean
c. Find the probability that a randomly selected district had fewer
than 1978 votes for President Clinton.
d. Find the probability that a randomly selected district had
between 2107 and 2224 votes for President Clinton.
e. Find the first quartile for votes for President Clinton. Round
your answer to the nearest whole number.
In: Statistics and Probability
n the 1992 presidential election, Alaska's 40 election districts
averaged 2118 votes per district for President Clinton. The
standard deviation was 578. (There are only 40 election districts
in Alaska.) The distribution of the votes per district for
President Clinton was bell-shaped. Let X = number of votes for
President Clinton for an election district. (Source: The World
Almanac and Book of Facts) Round all answers except part e. to 4
decimal places.
a. What is the distribution of X? X ~ N(,)
b. Is 2118 a population mean or a sample mean? Select an answer
Sample Mean Population Mean
c. Find the probability that a randomly selected district had fewer
than 1960 votes for President Clinton.
d. Find the probability that a randomly selected district had
between 2126 and 2364 votes for President Clinton.
e. Find the first quartile for votes for President Clinton. Round
your answer to the nearest whole number.
In: Statistics and Probability
14. (20 pts) This data shows the number of healthcare worker injuries in a hospital over the last 24 months.
| Month | Number of injuries |
| 1 | 9 |
| 2 | 6 |
| 3 | 6 |
| 4 | 6 |
| 5 | 5 |
| 6 | 1 |
| 7 | 3 |
| 8 | 8 |
| 9 | 5 |
| 10 | 4 |
| 11 | 4 |
| 12 | 7 |
| 13 | 8 |
| 14 | 6 |
| 15 | 9 |
| 16 | 8 |
| 17 | 5 |
| 18 | 5 |
| 19 | 8 |
| 20 | 7 |
| 21 | 7 |
| 22 | 10 |
| 23 | 8 |
| 24 | 6 |
The mean is 6.292.
(a) Using Goodness-of-fit test for Poisson, test if the data follows the Poisson distribution and determine λ.
(b) Using the mean computed from (a), Compute the probability that there will be more than 7 injuries next year.
(c) Using the mean computed from (a), compute the probability that there will be 5 or fewer injuries next year
In: Statistics and Probability
Have you ever tried to get out of jury duty? About 25% of those called will find an excuse (work, poor health, travel out of town, etc.) to avoid jury duty.†
(a) If 11 people are called for jury duty, what is the
probability that all 11 will be available to serve on the jury?
(Round your answer to three decimal places.)
(b) If 11 people are called for jury duty, what is the probability
that 5 or more will not be available to serve on the jury?
(Round your answer to three decimal places.)
(c) Find the expected number of those available to serve on the
jury. What is the standard deviation? (Round your answers to two
decimal places.)
| μ = people |
| σ = people |
(d) How many people n must the jury commissioner contact
to be 95.9% sure of finding at least 12 people who are available to
serve? (Enter your answer as a whole number.)
people
In: Math
The accompanying table describes results from groups of 8 births from 8 different sets of parents. The random variable x represents the number of girls among 8 children. Complete parts (a) through (d) below.
Click the icon to view the table.
a. Find the probability of getting exactly 6 girls in 8 births.
nothing
_____ (Type an integer or a decimal. Do not round.)
number of girls (x) P(x)
| Number of girls (x) | P(x) |
|---|---|
| 0 | 0.004 |
| 1 | 0.016 |
| 2 | 0.111 |
| 3 | 0.226 |
| 4 | 0.286 |
| 5 | 0.226 |
| 6 | 0.111 |
| 7 | 0.016 |
| 8 | 0.004 |
In: Statistics and Probability
How many people do you expected to arrive during a 45min period?Suppose that trees are distributed in a forest according to a two-dimensional Poisson process with parameter λ, the expected number of trees per acree, equal to 80.
In: Statistics and Probability
1.)
Forty
individuals independently construct a
98
%
confidence interval for the mean of a certain population. What is the expected number of individuals who will obtain confidence intervals that actually contain the mean of thepopulation
2.)Forty percent of the employees in a large corporation are registered in the corporation’s fitness program. If 3500 employees are selected at random from this corporation, what is the probability between 1410 and 1445, inclusive, will be registered in the fitness program? (Round to the nearest tenth of a percent.)
3.)
A
die
is to be tossed
291
times. Let X represent the number of times the
die
lands with
an odd number
showing. What is the
standard deviation
for X? (Round to the nearest hundredth.)
In: Statistics and Probability