Toledo Corp owns construction equipment worth $1.5M and has $500M in cash. Toledo Corp takes out a 5-year loan for $1M. Toledo Corp finances the construction of a new building entirely with cash. The cost of the construction is $1.5M. Please fill out Toledo Corp’s balance sheets shown below. The first balance sheet is before developing the new building and the second balance sheet is after developing the new building.

ANSWER

Toledo Corp’s balance sheets after taking the loan Before constructing the new building:

After constructing the new building:

Toledo Corp sells the building to Bechtel for 20,000 Bechtel shares @ $100/share. Please fill out Toledo Corp’s balance sheet after proceeds from the sale of the new building to Bechtel:

Between the beginning of 2020 and the middle of 2020,

A. the typical interest rate on jumbo mortgage went up, relative to the interest rate on conforming mortgages

B. the typical interest rate on conforming mortgages went up, relative to the interest rate on jumbo mortgages

Asia Pacific Ltd started operating on 1 July 2017 with 12 employees. Three years later all of those employees were still with the company. On 1 July 2019 the company hired 15 more people but by 30 June 2020 only 10 of those employed at the beginning of that year were still employed by Asia Pacific Ltd. All employees are entitled to 13 weeks’ long-service leave after a conditional period of 10 years of employment with Asia Pacific Ltd. At 30 June 2020 Asia Pacific Ltd estimates the following:

 The aggregate annual salaries of all employees hired on 1 July 2017 is now $1,200,000.

 The aggregate annual salaries of all current employees hired on 1 July 2019 is now $800,000.

 The probability that employees hired on 1 July 2017 will continue to be employed for the duration of the conditional period is 40 per cent.

 The probability that employees hired on 1 July 2019 will continue to be employed for the duration of the conditional period is 20 per cent.

 Salaries are expected to increase indefinitely at 1 per cent per annum.

The interest rates on high-quality corporate bonds are as follows:

Corporate bonds maturing in seven years 6% Corporate bonds maturing in eight years 8% Corporate bonds maturing in nine years 8% Corporate bonds maturing in ten years 10% At 30 June 2019 the provision for long-service leave was $12,000.

Required: a) Calculate the total accumulated long-service leave benefit as at 30 June 2020.

b) What amount should be reported for the long-service leave provision as at 30 June 2020 in accordance with AASB 119?

c) Prepare the journal entry for the provision for long-service leave for 30 June 2020 in accordance with AASB 119.

d) Which employee benefits are required to be discounted in accordance with AASB 119?

1. Your company wants to launch a new product. The price will be $108 and the projected units sold will be 5,000 each of the next five years and then zero sales after that (i.e. life of five years). Variable costs per unit is $47 and fixed costs will be $36,000 per year. This project will need initial net working capital of $37,000, and NWC will then increase $7,000 per year through the end of year five. At that point 75% of NWC (no tax ramifications) will be returned to the company. Necessary equipment investment will be $900,000 and have a salvage value of 23%, net of tax. The depreciation will be straight-line over the life of this project. Your company’s current debt/equity ratio is 1.15 and this product is in line with the operations of the rest of your company. Your company is in the 21% tax bracket. Your equity investors demand a 13% return and your company’s bonds yield 5.3%. Even though no debt will be used, you still need to use your company’s WACC. Price is accurate within 5%, units sold within 3%, and variable & fixed costs within 2%. What is the NPV in the worst-case scenario?

2.In 2020 and 2019, your cash was 4,563 and 3,597, your accounts receivables were 7,531 and 6,423, and your inventory was 10,235 and 11,563. Similiarly, in 2020 and 2019 your accounts payable was 8,423 and 5,789, and your other current liabilities were 7,413 and 10,356. Lastly from the balance sheet, in 2020 and 2019 your net fixed assets were 74,562 and 71,246.

In 2020 your net sales were 111,425, your costs of good sold was 38,999, rent was 48,543, and depreciation was 2,015. You paid interest of 1,728 and your tax rate was 20.36%.

What is cash flow from assets (i.e. free cash flow) in 2020?

Question 10 (1 point)

A restaurant wants to test a new in-store marketing scheme in a small number of stores before rolling it out nationwide. The new ad promotes a premium drink that they want to increase the sales of. 14 locations are chosen at random and the number of drinks sold are recorded for 2 months before the new ad campaign and 2 months after. The average difference in nationwide sales quantity before the ad campaign to after (after - before) is 2.9 with a standard deviation of 7. Using this information, they calculate a 95% confidence paired-t interval of (-1.14, 6.94). Which of the following is the best interpretation?

Question 10 options:

Question 11 (1 point)

Professors in the Economics Department at Western want to determine how challenging the program was for students. Out of a random sample of 24 students, 18 indicated that the program was either "challenging" or "very challenging". The 90% confidence interval estimating the proprotion of all students in the department who thought the program was challenging is given by which of the following?

Question 11 options:

Question 12 (1 point)

A medical researcher wants to determine if the average number of days spent in the hospital after a certain procedure is greater than 9.3 days. If the researcher conducts a hypothesis test, what will the null and alternative hypotheses be?

Question 12 options:

Question 13 (1 point)

A medical researcher wants to determine if the average hospital stay after a certain procedure is less than 14.97 days. The hypotheses for this scenario are as follows: Null Hypothesis: μ ≥ 14.97, Alternative Hypothesis: μ < 14.97. If the researcher randomly samples 26 patients that underwent the procedure and determines their average hospital stay was 15.68 days with a standard deviation of 7.183 days, what is the test statistic and p-value of this test?

Question 13 options:

Question 14 (1 point)

Do sit down restaurant franchises and fast food franchises differ significantly in stock price? Specifically, is the average stock price for sit-down restaurants greater than the average stock price for fast food restaurants? A hypothesis test for two independent samples is run on data recorded from the stock exchange and a p-value is calculated to be 0.4023. What is the appropriate conclusion?

Question 14 options:

Add a copy constructor for the linked list implementation below:

----------------------------------------------------------------------------------------------------------------------------------------------------

// list.cpp file

#include <string>
#include "list.h"

using namespace std;

Node::Node(string element)
{
data = element;
previous = nullptr;
next = nullptr;
}

List::List()
{
first = nullptr;
last = nullptr;
}

List::List(const List& rhs) // Copy constructor - homework
{
// Your code here
  
}

void List::push_back(string element)
{
Node* new_node = new Node(element);
if (last == nullptr) // List is empty
{
first = new_node;
last = new_node;
}
else
{
new_node->previous = last;
last->next = new_node;
last = new_node;
}
}

void List::insert(Iterator iter, string element)
{
if (iter.position == nullptr)
{
push_back(element);
return;
}

Node* after = iter.position;
Node* before = after->previous;
Node* new_node = new Node(element);
new_node->previous = before;
new_node->next = after;
after->previous = new_node;
if (before == nullptr) // Insert at beginning
{
first = new_node;
}
else
{
before->next = new_node;
}
}

Iterator List::erase(Iterator iter)
{
Node* remove = iter.position;
Node* before = remove->previous;
Node* after = remove->next;
if (remove == first)
{
first = after;
}
else
{
before->next = after;
}
if (remove == last)
{
last = before;
}
else
{
after->previous = before;
}
delete remove;
Iterator r;
r.position = after;
r.container = this;
return r;
}

Iterator List::begin()
{
Iterator iter;
iter.position = first;
iter.container = this;
return iter;
}

Iterator List::end()
{
Iterator iter;
iter.position = nullptr;
iter.container = this;
return iter;
}

Iterator::Iterator()
{
position = nullptr;
container = nullptr;
}

string Iterator::get() const
{
return position->data;
}

void Iterator::next()
{
position = position->next;
}

void Iterator::previous()
{
if (position == nullptr)
{
position = container->last;
}
else
{
position = position->previous;
}
}

bool Iterator::equals(Iterator other) const
{
return position == other.position;
}

----------------------------------------------------------------------------------------------------------------------------------------------------------------

Use the following header file, and test program (not to be modified) to verify that the copy constructor works correctly:

----------------------------------------------------------------------------------------------------------------------------------------------------------------

// list.h file

#ifndef LIST_H
#define LIST_H

#include <string>

using namespace std;

class List;
class Iterator;
//template <typename T>
class Node
{
public:
/**
Constructs a node with a given data value.
@param element the data to store in this node
*/
Node(string element); // Node(T element)
// Node(T data, Node<T>* n, Node<T>* n);
private:
string data; // T data;
Node* previous;
Node* next;
friend class List;
friend class Iterator;
};

class List
{
public:
/**
Constructs an empty list.
*/
List();
List(const List& rhs); // Homework
/*
Appends an element to the list.
@param element the value to append
*/
void push_back(string element);
/**
Inserts an element into the list.
@param iter the position before which to insert
@param element the value to insert
*/
void insert(Iterator iter, string element);
/**
Removes an element from the list.
@param iter the position to remove
@return an iterator pointing to the element after the
erased element
*/
Iterator erase(Iterator iter);
/**
Gets the beginning position of the list.
@return an iterator pointing to the beginning of the list
*/
Iterator begin();
/**
Gets the past-the-end position of the list.
@return an iterator pointing past the end of the list
*/
Iterator end();
private:
Node* first;
Node* last;
friend class Iterator;
};

class Iterator
{
public:
/**
Constructs an iterator that does not point into any list.
*/
Iterator();
/**
Looks up the value at a position.
@return the value of the node to which the iterator points
*/
string get() const;
/**
Advances the iterator to the next node.
*/
void next();
/**
Moves the iterator to the previous node.
*/
void previous();
/**
Compares two iterators.
@param other the iterator to compare with this iterator
@return true if this iterator and other are equal
*/
bool equals(Iterator other) const;
private:
Node* position;
List* container;
friend class List;
};

#endif

-----------------------------------------------------------------------------------------------------------------------------------------------------------------

// list_test .cpp file

#include <string>
#include <iostream>
#include "list.h"

using namespace std;

int main()
{
List names;

names.push_back("Tom");
names.push_back("Diana");
names.push_back("Harry");
names.push_back("Juliet");

// Add a value in fourth place

Iterator pos = names.begin();
pos.next();
pos.next();
pos.next();

names.insert(pos, "Romeo");

// Remove the value in second place

pos = names.begin();
pos.next();

names.erase(pos);

List names_copy(names); //Copy constructor - homework
names_copy.push_back("Shakespeare");
// Verify that Shakespeare was inserted.
cout << "Printing new list" << endl;
for (pos = names_copy.begin(); !pos.equals(names.end()); pos.next())
{
cout << pos.get() << endl; //
}
cout << "Printing original list " << endl;
for (pos = names.begin(); !pos.equals(names.end()); pos.next())
{
cout << pos.get() << endl;
}

return 0;
}

---------------------------------------------------------------------------------------------------------------------------------------------------------------

Thank you for your time and help!

The legitimacy of the Chinese government and its economic growth

Based on international standard both China and Singapore are considered as in authoritarian regime, simply saying individual freedoms are subordinate to the state, and there is no constitutional accountability. However, both of them achieved the economic success world-widely speaking. Singapore economy is one of the most stable in the world, with no foreign debt, high government revenue and a consistently positive surplus. China on the other hand, had become second largest economy in the world and was enjoying a very high growth rate of economy, but steadily growth of economy up until 2010 when it started slowed down after.

Question:

A) Why would a slowing growth economy be considered as a threat to the legitimacy of the Chinese Communist Party? (200-300 words)

B) Why did Chinese Communist Party look to Singapore for inspiration of ruling and developing economy? (200-300 words)

The PC Supply manufactures memory cards that sell to wholesalers for $2.00 each. Variable and fixed costs are as follows: Variable Costs per card Fixed Costs per Month Manufacturing Direct materials $0.30 Direct labor 0.25 Factory overhead 0.25 0.80 Factory overhead $4,000 Selling and admin. 0.15 Selling and admin. 3,000 Total $0.95 Total $7,000 PC Supply produced and sold 10,000 cards during October 2010. There were no beginning or ending inventories.

a. Prepare a contribution income statement for the month of October.

b. Determine PC Supply’s monthly break-even point in units.

c. Determine the effect on monthly profit of a 1,100 unit increase in monthly sales.

d. If PC Supply is subject to an income tax of 28 percent, determine the dollar sales volume is required to earn a monthly after-tax profit of $22,000.

Jamaica Ltd was incorporated on 1 July 2019 and on the same day, the company purchased the net assets of Smart Corporation by issuing 120 000 ordinary shares at a price of $8 per share. The shares were fully paid.
On 5 August 2019, the company issued a prospectus to the public, offering;

150,000 10% preference shares for $12 payable $8 on application and the remaining on allotment; as well as 250,000 ordinary shares at an issue price of $10, payable on the following terms;

• $3 on application

• $3 on allotment

• $2 on call one

• $2 on call two.

  Call one to be made one month after the date of allotment, and call two to be made three months after the date of allotment.

  If required, the issue is underwritten for a commission of $4,000.

When applications closed on 30 August 2019, applications had been received for 120,000 preference shares and 355,000 ordinary shares, including one applicant for 25,000 ordinary shares who had paid in full.

On 12 September 2019, the directors allotted the shares as follows;

1. Preference shares: the successful applicants were allotted the preference shares.

2. Ordinary shares:

   1. 25,000 ordinary shares were allotted to the applicant who paid for the shares in full.

   2. Applicants for 15,000 ordinary shares were refunded their application money in full.

   3. The remaining applicants were allotted 5 ordinary shares for every 7 shares

      applied for. The excess application money on these shares was to be offset

      against the amount payable on allotment.

1

The share issue costs, for ordinary shares, were $3,200 and were paid on 20 September 2019.

All allotment money was received by 25 September 2019 including the amount due from the underwriter. The underwriting commission was paid on this date.

The two calls were made on the dates stated in the prospectus, and a month after each call, monies were received, except that the holders of 15,000 ordinary shares who did not pay either calls.

In addition, a holder of another 10,000 ordinary shares did not pay the second call.

On 20 January 2020, the board of directors decided to forfeit the shares who had not paid for the calls. The shares were reissued for $6.50 per share the next day and the reissue cost was $1,800.

Required:

Prepare the general journal entries to record the above transactions.

Instructions: You are required to complete:

• General journal entries

• Workings and calculations (for instance any relevant T accounts or tables).

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