Rebecca wishes to estimate the mean number of miles that her Nissan Versa can drive on a full tank of gas. She fills up her car with regular unleaded gasoline from the same station 9 times and records the number of miles that she drives until her low tank indicator light comes on. Construct a 96% confidence interval for the mean number of miles that she can drive on a full tank of gas until the low tank indicator light will turn on. Round to the nearest 0.1 miles
203 325 119 345 405 300 450 267 472
In: Statistics and Probability
In: Statistics and Probability
This problem requires you to prompt the user for some information, and apply simple arithmetic operation to generate an output.
We all know that driving is expensive. So let's write a program to observe this.
You should prompt the user with the words: Enter miles per gallon: at which time the users enters a number, and then Enter the gas price:at which time the user enters the second number. The prompts must be EXACTLY as written, including the colon (:) character, or your test cases will fail. Since you are prompting the user for input, you should not enter anything into the (optional) input box below, but input your numbers after your prompts.
Both inputs should be read as float data type , and your program will output the gas cost for 10 miles, 50 miles, and 400 miles. Due to the way floating point numbers are internally stored, there can be some discrepancies with the precision of calculations depending on the order things are done. To prevent this from causing your submission to be marked incorrect, please calculate the cost in the following order: The miles increment (10, 50, or 400) multiplied by 1.0/miles per gallon multiplied by the gas price.
Example: If the input is:
Enter miles per gallon:20.0 Enter the gas price:3.1599
Then the output is:
1.57995 7.89975 63.198
Note: Real per-mile cost would also include maintenance and depreciation.
Someone please help! Can't get it right! (This is python)
In: Computer Science
a. As the Head of Business Development of Fidelity Venture Capital, a client has presented a business plan that has the following projected returns for your consideration;
Stock A Stock B
State of the Economy Returns / Prob Returns / Prob
Excellent 32% / 0.4 40% / 0.2
Worse -5% / 0.4 8% / 0.3
Normal 21. % / 0.2 25% / 0.5
Required:
i. Calculate the expected return for each stock
ii. Calculate the total risk of the client’s business for each stock
iii. If your client plans investing equally in each stock, with a correlation coefficient of -0.8, what is the portfolio return and portfolio risk?
iv. If the beta of the client’s business is 0.9 and the risk free rate is 22%, calculate the required rate of investment if the market risk premium is 4%.
In: Finance
A fire insurance company thought that the mean distance from a home to the nearest fire department in a suburb of Chicago was at least 5.9 miles. It set its fire insurance rates accordingly. Members of the community set out to show that the mean distance was less than 5.9 miles. This, they thought, would convince the insurance company to lower its rates. They randomly indentified 60 homes and measured the distance to the nearest fire department from each. The resulting sample mean was 5.3. If σ = 2.2 miles, does the sample show sufficient evidence to support the community's claim at the α = .05 level of significance?
(a) Find z. (Give your answer correct to two decimal places.)
(ii) Find the p-value. (Give your answer correct to four decimal places.)
(b) State the appropriate conclusion. Reject the null hypothesis, there is not significant evidence that the mean distance is less than 5.9 miles. Reject the null hypothesis, there is significant evidence that the mean distance is less than 5.9 miles. Fail to reject the null hypothesis, there is significant evidence that the mean distance is less than 5.9 miles. Fail to reject the null hypothesis, there is not significant evidence that the mean distance is less than 5.9 miles.
You may need to use the appropriate table in Appendix B to answer this question.
In: Statistics and Probability
Units of Activity Depreciation Calculation:
Deprec. Cost per Unit Rate= _Cost – Salvage Value
Estimated Usage
Depre. Exp. = Actual Usage * Deprec. Cost per Unit Rate
Calculate Units of Activity Depreciation for each year:
Depre. Cost per Unit Rate= _Cost – Salvage Value = $
Estimated Usage
2018 Depreciation: 10,000 miles *$0.18= $1,800
2019 Depreciation: 20,000 miles*
2020 Depreciation: 25,000 miles *
2021 Depreciation: 20,000 miles*
2022 Depreciation: 15,000 miles*
2023 Depreciation: 10,000 miles*
|
Date |
Accounts |
Debit |
Credit |
|
12/31/18 |
Depreciation Expense - Truck |
$1,800 |
|
|
Accumulated Deprec. - Truck |
$1,800 |
The journal entry to record the Depreciation Expense for Year 2 is:
|
Date |
Accounts |
Debit |
Credit |
|
12/31/19 |
|||
The journal entry to record the Depreciation Expense for Year 3 is:
|
Date |
Accounts |
Debit |
Credit |
|
12/31/20 |
|||
The journal entry to record the Depreciation Expense for Year 4 is:
|
Date |
Accounts |
Debit |
Credit |
|
12/31/21 |
|||
In: Accounting
HW #44. 5
The manufacturer of a particular brand of tires claims they average at least 50,000 miles before needing to be replaced. From past studies of this tire, it is known that the population standard deviation is 8,000 miles.
A survey of tire owners was conducted. From the 23 tires surveyed, the mean lifespan was 45500 miles. Using alpha = 0.05, can we prove that the data in inconsistent with the manufacturers claim?
We should use a ? t z test.
What are the correct hypotheses?
H0: Select an answer s μ s² x̄ p̂ σ p σ² ? =
< ≠ ≥ ≤ >
HA: Select an answer σ p μ p̂ x̂ σ² s s² ? ≤
= < ≠ > ≥
Based on the hypotheses, find the following:
Test Statistic=
p-value=
The correct decision is to Select an answer Fail to reject the null hypothesis Reject the null hypothesis Accept the alternative hypotheis Accept the null hypothesis .
The correct conclusion would be: Select an answer There is not enough evidence to conclude that the tires last fewer miles than claimed There is enough evidence to conclude that the tires last fewer miles than claimed There is enough evidence to conclude that the tires do not last fewer miles than claimed There is not enough evidence to conclude that the tires do not last fewer miles than claimed .
In: Statistics and Probability
On November 1, 2015 Polo company purchased a truck that has a cost
of $40,000 and a salvage value of $4,000. The truck is expected to
be driven during its 6 years of useful life as follows: 2015,
15,000 miles; 2016, 15,000 miles; 2017, 20,000 miles; 2018, 30,000
miles 2019, 10,000 miles and 2020, 10,000 miles. Polo Company uses
units of activity method of depreciation
.
1- What is the total units of activity?
a) $40,000
b) $4,000
c) $36,000
d) 100,000 miles
2- What is the depreciable cost per unit? *
a) $36,000
b) $0.36 per mile
c) $0.4 per mile
d) $0.04 per mile
3- What is the depreciation expense for the year 2015? *
a) $6,000
b) $1,000
c) $5,400
d) $900
4- What is the book value for the year 2016? *
a) $34,600
b) $29,200
c) $22,000
d) $33,700
5- If the Polo Company uses the double declining balance (DDB)
method, what is the annual depreciation expense for the year 2015?
*
a) $13,333.33
b) $1,111.11
c) $2,222.22
d) None of the above
6- If the truck was purchased on August 1, 2015, what is the
depreciation expense for the year 2015 under units of activity
method? *
a) $5,400
b) $2,250
c) $2,700
d) $3,150
In: Accounting
In: Statistics and Probability
The average gas mileage of a certain model car is 28.0 miles per gallon. If the gas mileages are normally distributed with a standard deviation of 0.4 miles per gallon, find the probability that a car has a gas mileage of between 26.8 and 27.2 miles per gallon. In addition to the answer, please write out your steps and thoughts that led you to your answer.
In: Statistics and Probability