The market and Stock A have the following probability distributions:
| Probability | Return on Market | Return on Stock A |
| 0.15 | 15% | 18% |
| 0.3 | 12% | 15% |
| 0.55 | 10% | 11% |
a. Calculate the expected rates of return for the market and Stock A.
b. Calculate the standard deviations for the market and Stock A.
c. Calculate the coefficient of variation for the market and Stock A.
In: Finance
Andi and Budi will meet. Suppose A is an event where Andi arrives late, and B is an event where Budi arrives late, with P (A) = 0.1 and P (B) = 0.3. What is the chance the two of them will meet on time if
a. Genesis A and B are independent
(independent)?
b. P (B | A) = 0.5?
c. P (B | A) = 0.1?
In: Math
What is the overall efficiency for the removal with the fabric filter for a distribution of particles where 0.05% of the particles are of 0.1 microns diameter, 0.2% of particles are of 0.3 microns diameter, 2.8% of the particles are 0.7 microns and remaining particles are in the particle diameter range of 1 to 50 microns.
| A. |
99% |
|
| B. |
92% |
|
| C. |
37% |
|
| D. |
89% |
In: Civil Engineering
ANT 120
Lab 1: The Forces of Evolution
There are four mechanisms that can lead to evolutionary change from one generation to the next: mutation, natural selection, gene flow, and genetic drift. In this laboratory exercise we will examine the action of genetic drift and natural selection. The key difference between these two mechanisms, which can be difficult to get a handle on without direct experimentation, is that natural selection privileges some individuals over others on the basis of their biological traits while genetic drift privileges some individuals over others with no regard to their biological traits.
Data Table for Genetic Drift Experiment
|
Frequency of black beetles (alleles) |
|||||||||||
|
Generation |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
|
Round 1 |
0.5 |
0.5 |
0.6 |
0.6 |
0.5 |
0.4 |
0.6 |
0.8 |
0.9 |
0.8 |
0.7 |
|
Round 2 |
0.5 |
0.4 |
0.4 |
0.5 |
0.3 |
0.2 |
0.2 |
0.3 |
0.1 |
0.0 |
0.0 |
Data Table for Natural Selection Experiment
|
Frequency of black beetles (alleles) |
|||||||||||
|
Generation |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
|
Green Forest |
0.5 |
0.5 |
0.5 |
0.4 |
0.2 |
0.2 |
0.3 |
0.3 |
0.2 |
0.1 |
0.0 |
|
Black dirt |
0.5 |
0.6 |
0.6 |
0.7 |
0.8 |
10.0 |
10.0 |
10.0 |
10.0 |
10.0 |
10.0 |
Using the data, answer the questions on the other side of this sheet.
Questions
1. Compare the results from the genetic drift experiments to the natural selection experiments. Are there any clear differences in the results? If so, what is the reason for the differences?
2. In cases where one of the colors of beetle was eliminated, how could the allele for this color re-enter the population? Which forces of evolution would be required?
3. From these experiments, how might genetic drift and natural selection affect natural populations of organisms differently? If the population of beetles was 20,000 instead of 20 (and 10,000 survived each generation) how would this influence the effects of genetic drift vs. natural selection?
4. Is the outcome of genetic drift or natural selection more predictable? How might these different mechanisms of evolutionary change relate to functional traits of organisms?
In: Biology
ANT 120
Lab 1: The Forces of Evolution
There are four mechanisms that can lead to evolutionary change from one generation to the next: mutation, natural selection, gene flow, and genetic drift. In this laboratory exercise we will examine the action of genetic drift and natural selection. The key difference between these two mechanisms, which can be difficult to get a handle on without direct experimentation, is that natural selection privileges some individuals over others on the basis of their biological traits while genetic drift privileges some individuals over others with no regard to their biological traits.
Data Table for Genetic Drift Experiment
|
Frequency of black beetles (alleles) |
|||||||||||
|
Generation |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
|
Round 1 |
0.5 |
0.5 |
0.6 |
0.6 |
0.5 |
0.4 |
0.6 |
0.8 |
0.9 |
0.8 |
0.7 |
|
Round 2 |
0.5 |
0.4 |
0.4 |
0.5 |
0.3 |
0.2 |
0.2 |
0.3 |
0.1 |
0.0 |
0.0 |
Data Table for Natural Selection Experiment
|
Frequency of black beetles (alleles) |
|||||||||||
|
Generation |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
|
Green Forest |
0.5 |
0.5 |
0.5 |
0.4 |
0.2 |
0.2 |
0.3 |
0.3 |
0.2 |
0.1 |
0.0 |
|
Black dirt |
0.5 |
0.6 |
0.6 |
0.7 |
0.8 |
10.0 |
10.0 |
10.0 |
10.0 |
10.0 |
10.0 |
After tabulating your data, answer the questions on the other side of this sheet.
Questions
Compare the results from the genetic drift experiments to the natural selection experiments. Are there any clear differences in the results? If so, what is the reason for the differences?
In cases where one of the colors of beetle was eliminated, how could the allele for this color re-enter the population? Which forces of evolution would be required?
From these experiments, how might genetic drift and natural selection affect natural populations of organisms differently? If the population of beetles was 20,000 instead of 20 (and 10,000 survived each generation) how would this influence the effects of genetic drift vs. natural selection?
Is the outcome of genetic drift or natural selection more predictable? How might these different mechanisms of evolutionary change relate to functional traits of organisms?
In: Biology
The drive-up window at a local bank is searching for ways to improve service. One of the tellers has decided to keep a control chart for the service time in minutes for the first four customers driving up to her window each hour for a three-day period. The results for her data collection appear below:
|
Customer |
TIME |
||||||||
|
9 am |
10 am |
11 am |
12 |
1 pm |
2 pm |
3 pm |
4 pm |
||
|
1 |
1.4 |
3.8 |
3.6 |
4.3 |
4.0 |
1.3 |
0.9 |
4.7 |
|
|
2 |
2.3 |
5.2 |
2.5 |
1.2 |
5.2 |
1.1 |
4.4 |
5.1 |
|
|
3 |
1.9 |
1.9 |
0.8 |
3.0 |
2.7 |
4.9 |
5.1 |
0.9 |
|
|
4 |
5.1 |
4.8 |
2.9 |
1.5 |
0.3 |
2.3 |
4.6 |
4.7 |
|
|
Customer |
TIME |
||||||||
|
9 am |
10 am |
11 am |
12 |
1 pm |
2 pm |
3 pm |
4 pm |
||
|
1 |
2.8 |
0.5 |
4.5 |
0.6 |
4.8 |
2.7 |
4.2 |
0.9 |
|
|
2 |
3.0 |
2.7 |
1.9 |
1.2 |
2.8 |
2.0 |
1.1 |
4.4 |
|
|
3 |
4.1 |
4.7 |
4.2 |
2.7 |
1.1 |
2.6 |
4.4 |
0.6 |
|
|
4 |
4.8 |
3.6 |
0.4 |
2.5 |
0.4 |
2.6 |
3.1 |
0.4 |
|
|
Customer |
TIME |
||||||||
|
9 am |
10 am |
11 am |
12 |
1 pm |
2 pm |
3 pm |
4 pm |
||
|
1 |
0.3 |
3.5 |
5.2 |
2.9 |
3.3 |
4.0 |
2.8 |
0.6 |
|
|
2 |
2.4 |
3.4 |
0.3 |
1.9 |
3.7 |
3.3 |
0.7 |
2.1 |
|
|
3 |
5.0 |
4.6 |
2.4 |
0.8 |
3.8 |
5.0 |
1.6 |
3.3 |
|
|
4 |
0.9 |
3.3 |
3.9 |
0.3 |
2.1 |
2.8 |
4.6 |
2.7 |
|
Using Minitab:
if it's possible i need the minitab file or link for it
In: Statistics and Probability
Project 10-1 Convert lengths In this assignment, you’ll add code to a form that converts the value the user enters based on the selected conversion type. The application should handle the following conversions:
From To Conversion
Miles - Kilometers: 1 mile = 1.6093 kilometers
Kilometers - Miles: 1 kilometer = 0.6214 miles
Feet - Meters: 1 foot = 0.3048 meters
Meters - Feet: 1 meter = 3.2808 feet
Inches - Centimeters: 1 inch = 2.54 centimeters
Centimeters - Inches: 1 centimeter = 0.3937 inches
Feet - Yards: 1 foot = 0.333333 yards
Yards - Feet: 1 yard = 3 feet
1. Open the Conversions project. Display the code for the form, and notice the rectangular array whose rows contain the value to be displayed in the combo box, the text for the labels that identify the two text boxes, and the multiplier for the conversion as shown above.
2. Set the DropDownStyle property of the combo box so the user must select an item from the list.
3. Add the 2 additional conversion units for feet and yards to the array.
4. Add code to load the combo box (use the load event) with the first element in each row of the rectangular array a. display the first item in the combo box when the form is loaded. (I need to figure out how to grab from the array and not from a list)
5. Add code to: a. change the labels for the text boxes (When the user selects a conversion, the label for the textboxes should reflect that selection.) b. clear the calculated length c. move the focus to the entry text box when the user selects a different item from the combo box.
6. Rename the form to frmConversions.
7. Test the application to be sure the conversions are displayed in the combo box, the first conversion is selected by default, and the labels change appropriately when a different conversion is selected.
8. Add code to calculate and display the converted length when the user clicks the Calculate button. To calculate the length, you can get the index for the selected conversion and then use that index to get the multiplier from the array. Test the application to be sure this works correctly.
9. Add code to check that the user enters a valid decimal value for the length. Then, test the application one more time to be sure the validation works correctly.
Code Given:
Public Class frmConversions
Dim conversionTable(,) As String = {
{"Miles to kilometers", "Miles", "Kilometers", "1.6093"},
{"Kilometers to miles", "Kilometers", "Miles", "0.6214"},
{"Feet to meters", "Feet", "Meters", "0.3048"},
{"Meters to feet", "Meters", "Feet", "3.2808"},
{"Inches to centimeters", "Inches", "Centimeters", "2.54"},
{"Centimeters to inches", "Centimeters", "Inches", "0.3937"},
{"Feet to Yards", "Feet", "Yards", " 0.333333"},
{"Yards to Feet", "Yards", "Feet", "3"}}
Public Function IsPresent(ByVal textbox As TextBox, ByVal name
As String) _
As Boolean
If textbox.Text = "" Then
MessageBox.Show(name & " is a required field.", "Entry
Error")
textbox.Select()
Return False
Else
Return True
End If
End Function
Public Function IsDecimal(ByVal textbox As TextBox, ByVal name
As String) _
As Boolean
Dim number As Decimal = 0
If Decimal.TryParse(textbox.Text, number) Then
Return True
Else
MessageBox.Show(name & " must be a decimal value.", "Entry
Error")
textbox.Select()
textbox.SelectAll()
Return False
End If
End Function
Private Sub btnCalculate_Click(sender As Object, e As EventArgs) Handles btnCalculate.Click
End Sub
Private Sub cboConversions_SelectedIndexChanged(sender As Object, e As EventArgs) Handles cboConversions.SelectedIndexChanged
End Sub
Private Sub btnExit_Click(ByVal sender As System.Object,
ByVal e As System.EventArgs) Handles btnExit.Click
Me.Close()
End Sub
Private Sub Form1_Load(sender As Object, e As EventArgs) Handles MyBase.Load
End Sub
In: Physics
Use the appropriate formula to determine the most probable speed (in miles per hour) for N2 molecules at 3.00 x 102 K. (As you do this, be sure to show your units explicitly.) Repeat the calculation for N2 molecules at 1.00 x 103 K.
In: Chemistry
Airlines and hotels give bonus frequent-flyer miles, gifts, and free companion tickets to attract the business traveler. These promotions are often provided in lieu of a price cut. The traveler benefits personally, although their company does not get the benefit of lower rates. Is this ethical?
In: Accounting
In: Physics