Questions
f(x,y) = 2/7(2x + 5y) for 0 < x < 1, 0 < y < 1...

f(x,y) = 2/7(2x + 5y) for 0 < x < 1, 0 < y < 1

given X is the number of students who get an A on test 1

given Y is the number of students who get an A on test 2

find the probability that more then 90% students got an A test 2 given that 85 % got an A on test 1

In: Statistics and Probability

Question 5 i) The make‐up for students missing the mid‐term will be at 7:30am. Explain why...

Question 5

i) The make‐up for students missing the mid‐term will be at 7:30am. Explain why this professor likes this policy?

[Hint: Make ups are extra work of the graders, and many students don’t like it that early]   [Note: Sickness is a choice variable for students who miss an exam]

ii) Also, use game theory to model this situation.

In: Economics

A random sample of 1200 NAU students in Flagstaff found 384 NAU students who drink coffee...

A random sample of 1200 NAU students in Flagstaff found 384 NAU students who drink coffee daily. Find a 95% confidence interval for the true percent of NAU students in Flagstaff who drink coffee daily. Express your results to the nearest hundredth of a percent. .

Answer: _______ to _______ %

Please include work so I may better understand the problem.

In: Statistics and Probability

Scores for college bound students on the SAT Critical Reading test in recent years follow approximately...

Scores for college bound students on the SAT Critical Reading test in recent years follow approximately the Normal (500, 1202) distribution.

10. How high must a student score to place in the top 10% of all students taking the SAT?

11. Suppose we randomly select 4 students. What is the probability their average score is between 400 and 600?

In: Statistics and Probability

The national average of college students on a test of sports trivia is 50 with a...

The national average of college students on a test of sports trivia is 50 with a standard deviation of 5. A sportscaster is interested in whether BC students know less about sports than the national average. The sportscaster tests a random sample of 25 BC students and obtains a mean of 48 Use an alpha level of 0.05. Is this a one-tailed or two tailed test?

In: Statistics and Probability

A psychology major recently conducted a survey with a random sample of 38 undergraduate students. She...

A psychology major recently conducted a survey with a random sample of 38 undergraduate students. She found that 18% of those surveyed stated that their preferred superpower would be teleportation. An article in a popular magazine stated that 33% of college students would choose teleportation as their preferred superpower. At Alpha = 0.10, test the claim that the proportion of students preferring teleportation is less than 33%?

In: Statistics and Probability

Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying...

Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 29 ​students, she finds 4 who eat cauliflower. Obtain and interpret a 95​% confidence interval for the proportion of students who eat cauliflower on​ Jane's campus using Agresti and​ Coull's method. LOADING... Click the icon to view Agresti and​ Coull's method.

In: Statistics and Probability

The mean weight of 500 students at a certain college is 151 lb and the standard...

The mean weight of 500 students at a certain college is 151 lb and the standard deviation is 15 lb. Assume that the weights are normally distributed.
a.) How many students weigh between 120 and 155 lb? (ANSWER IN WHOLE NUMBER)

b.) What is the probability that randomly selected male students to weigh less than 128 lb? (ANSWER IN 4 DECIMAL NUMBER)

In: Statistics and Probability

A recent study from the Department of Education shows that approximately 11% of students are in...

A recent study from the Department of Education shows that approximately 11% of students are in private schools. A random sample of 450 students from a wide geographic area indicated that 55 attended private schools.

a) Estimate the true proportion of students attending private schools with 95% confidence.

b) Are the study results by the Department of Education consistent with the sample? Why or why not?

In: Statistics and Probability

1. For all U.S. students nationally who take the SAT, SAT Math scores are normally distributed...

1. For all U.S. students nationally who take the SAT, SAT Math scores are normally distributed with an average score of 500 for all U.S. students . A random sample of 100 students entering Whitmer College had an average SAT Math (SAT-M) score of 520 and a sample standard deviation of 120.

The sample data can be used to test the claim that the mean SAT-M score of all Whitmer College students is different than the national mean SAT-M score.

Based on the given information and using the appropriate formula, calculate the test statistic for this hypothesis test. Round your answer to two decimal places. Enter the numeric value of the test statistic in the space below:

2. For all U.S. students nationally who take the SAT, SAT Math scores are normally distributed with an average score of 500 for all U.S. students . A random sample of 100 students entering Whitmer College had an average SAT Math (SAT-M) score of 475 and a sample standard deviation of 120.

The sample data can be used to test the claim that the mean SAT-M score of all Whitmer College students is different than the national mean SAT-M score.

Based on the given information, use the appropriate formula and the provided Standard Normal Table (Z table). Determine the p-value for this two-sided hypothesis test. You will need to calculate the test statistic first. Enter the p-value in the space below as a decimal rounded to four decimal places:

3. For all U.S. students nationally who take the SAT, SAT Math scores are normally distributed with an average score of 500 for all U.S. students . A random sample of 100 students entering Whitmer College had an average SAT Math (SAT-M) score of 520 and a sample standard deviation of 120.

The sample data can be used to test the claim that the mean SAT-M score of all Whitmer College students is different than the national mean SAT-M score.

Based on the given information, use the appropriate formula and the provided Standard Normal Table (Z table). Determine the p-value for this two-sided hypothesis test. You will need to calculate the test statistic first. Enter the p-value in the space below as a decimal rounded to four decimal places:

In: Statistics and Probability