I need to write an essay on: cause and effect/ USA spends about 54% of its total federal budget on the Military. Military spending in the USA is far greater than any nation in the world. (USA spends more on military than the next 10 highest spenders combined, 4 times China who is second on the list etc) Why does USA need to spend so much more on its military than other countries (cause), and what is/are the results of all this spending (effect)?

Create an essay which supports some position on an issue related to the following 3 topics and support by showing causes and effects. Although there are many possible strategies, most students will find it easier to focus a thesis statement a limited number of causes and effects or even on a single most important example. This will allow the essay to develop a sufficient depth. The essays should not be a simple list of causes or effects, but an essay that takes a position on why a condition exists and or argues the results of this condition. Some writers may even be able to create a strong focused thesis by suggesting a solution or arguing for some clear change of policy. The goal is to create an essay that allows you to develop a position or argument in a cause and effect essay. A strong thesis statement is very important and students should underline it in the final draft of their essay.

This essay will require research and a good deal of time learning about your chosen topic, so make sure to plan ahead and give yourself enough time to learn before you start writing.

Essay should be 4 pages long and it must have a minimum of 3 academic sources—no Wikipedia, encyclopedias, dictionaries etc. Use the library resources to find legitimate, academic sources. The Riverland Library and the library’s web site offer many useful databases and resources for researchers. Most of these sources are consider academic good, sources. I suggest you get comfortable with library and its research tools because you will need to use effective source material for our last two essays.

Modify StudentLinkedList class by adding the following methods:

printStudentList: print by calling and printing “toString” of every object in the linkedList. Every student object to be printed in a separate line.

 deleteStudentByID(long id): delete student object from the list whose ID is matching with the passed parameter.

 sortListByID(): sort the linkedlist according to students IDs.

 findMarksAverage(): find the average of all marks for all students in the list.

 findMinMark(int markIndex): find the student with the minimum mark in a specific index:

o 0: Quizzes

o 1: Midterm Exam

o 2: Final Exam

import java.util.LinkedList;

public class StudentLinkedList {

public static void main(String[] args) {

LinkedList linkedlist = new LinkedList();

linkedlist.add(new Student("Ahmed Ali", 20111021, 18, 38, 38));

linkedlist.add(new Student("Sami Kamal", 20121021, 17, 39, 35));

linkedlist.add(new Student("Salem Salim", 20131021, 20, 40, 40));

linkedlist.add(new Student("Rami Mohammed", 20111031, 15, 35, 30));

linkedlist.add(new Student("Kim Joe", 20121024, 12, 32, 32));

linkedlist.addFirst(new Student("Hadi Ali", 20111025, 19, 38, 39));

linkedlist.addLast(new Student("Waleed Salim", 20131025, 10, 30, 30));

linkedlist.set(0, new Student("Khalid Ali", 20111027, 15, 30, 30));

linkedlist.removeFirst(); linkedlist.removeLast();

linkedlist.add(0, new Student("John Don", 20131025, 11, 31, 31));

linkedlist.remove(2);

}

class Student{

private String name;

private Long ID;

private int [] marks = new int [3];

public Student(String name, long ID, int quizzes, int mid, int fin) {

this.name = name; this.ID = ID;

marks[0] = quizes;

marks[1] = mid;

marks[2] = fin;

}

public String getName() {

return name;

}

public Long getID() {

return ID;

}

public int[] getMarks() {

return marks;

}

@Override public String toString() { String temp = "student: " + "name = " + name + ", ID = " + ID + ", marks = {" + marks[0] + ", " + marks[1] + ", " + marks[2] + "}"; return temp; }

}

On average, Americans have lived in 2 places by the time they are 18 years old. Is this average more for college students? The 57 randomly selected college students who answered the survey question had lived in an average of 2.17 places by the time they were 18 years old. The standard deviation for the survey group was 0.8. What can be concluded at the αα = 0.10 level of significance?

1. For this study, we should use Select an answer t-test for a population mean z-test for a population proportion
2. The null and alternative hypotheses would be:

H0:  ? p μ  ? = ≠ < > _________

H1:  ? p μ  ? < = ≠ > _________   

3. The test statistic ? z t  =______________ (please show your answer to 2 decimal places.)
4. The p-value =______________________ (Please show your answer to 4 decimal places.)
5. The p-value is ? ≤ >  α
6. Based on this, we should Select an answer fail to reject reject accept  the null hypothesis.g
7. Thus, the final conclusion is that ...
   • The data suggest that the populaton mean is significantly more than 2 at αα = 0.10, so there is statistically significant evidence to conclude that the population mean number of places that college students lived in by the time they were 18 years old is more than 2.
   • The data suggest that the population mean is not significantly more than 2 at αα = 0.10, so there is statistically insignificant evidence to conclude that the population mean number of places that college students lived in by the time they were 18 years old is more than 2.
   • The data suggest that the sample mean is not significantly more than 2 at αα = 0.10, so there is statistically insignificant evidence to conclude that the sample mean number of places that college students lived in by the time they were 18 years old is more than 2.17.
8. Interpret the p-value in the context of the study.
   • If the population mean number of places that college students lived in by the time they were 18 years old is 2 and if you survey another 57 college students then there would be a 5.71323686% chance that the population mean number of places that these college students lived in by the time they were 18 years old would be greater than 2.
   • If the population mean number of places that college students lived in by the time they were 18 years old is 2 and if you survey another 57 college students then there would be a 5.71323686% chance that the sample mean for these 57 college students would be greater than 2.17.
   • There is a 5.71323686% chance of a Type I error.
   • There is a 5.71323686% chance that the population mean number of places that college students lived in by the time they were 18 years old is greater than 2 .
9. Interpret the level of significance in the context of the study.
   • If the population mean number of places that college students lived in by the time they were 18 years old is more than 2 and if you survey another 57 college students, then there would be a 10% chance that we would end up falsely concuding that the population mean number of places that college students lived in by the time they were 18 years old is equal to 2.
   • If the population mean number of places that college students lived in by the time they were 18 years old is 2 and if you survey another 57 college students, then there would be a 10% chance that we would end up falsely concuding that the population mean number of places that college students lived in by the time they were 18 years old is more than 2.
   • There is a 10% chance that the population mean number of places that college students lived in by the time they were 18 years old is more than 2.
   • There is a 10% chance that none of this is real since you have been hooked up to virtual reality since you were born.

Most students attending Faulkner University are older than the typical college entry age of 18. HRM students tend to be even older than the Faulkner average. Your own class of 17 students has an average age of 31.7, with a standard deviation of 6.7. If the average age of all students attending Faulkner at all campuses is 25.25, is your class significantly older? When I mean significantly older, I mean at the 95% level.

Sample mean of your class’ age = ____

Population mean of all HRM students’ age (μ) = ____

Standard deviation = ____

Sample size (n) = ____

Standard error of the mean = ____

z-score = _____

Is the average age of your HRM class significantly older?     Yes __              No __

How old are college students? The national age distributions for college students are shown below. The Western Association of Mountain Colleges took a random sample of 212 students and obtained the sample distribution listed second. Is the sample age distribution for the Western Association of Mountain Colleges a good fit to the national distribution? Use α = 0.05

National Age Distribution for College Students

Sample Distribution, Western Association of Mountain Colleges

Using diaries for many weeks, a study on the lifestyles of visually impaired students was conducted. The students kept track of many lifestyle variables including how many hours of sleep obtained on a typical day. Researchers found that visually impaired students averaged 9.6 hours of sleep, with a standard deviation of 1.21 hours. Assume that the number of hours of sleep for these visually impaired students is normally distributed.

(a) What is the probability that a visually impaired student gets less than 6.9 hours of sleep? answer: 0.0129

(b) What is the probability that a visually impaired student gets between 6.6 and 10.53 hours of sleep? answer: .7728

(c) Fourty percent of students get less than how many hours of sleep on a typical day? answer:

There are two types of potential members for a new gym—students and adults. The new gym owner would like to give students a discounted price in order to attract more students to her gym. The gym’s MC=4. Which of the following sets of demand curves for students (S) and adults (A) would allow the gym owner to engage in third-degree price discrimination and charge a lower price to the students?

Group of answer choices

None of the other answers is correct.

pa = 40 - 2qa, ps = 40 - 4qs

pa = 20 - 4qa,ps = 20 - 2qs

pa=20 - 2qa, ps = 36- 2qs

_{pa = 25 - 3qa, ps = 30 - 3qs}

None of the other answers is correct.

None of the other answers is correct.

9.1.2

Many high school students take the AP tests in different subject areas. In 2007, of the 144,796 students who took the biology exam 84,199 of them were female. In that same year, of the 211,693 students who took the calculus AB exam 102,598 of them were female ("AP exam scores," 2013). Estimate the difference in the proportion of female students taking the biology exam and female students taking the calculus AB exam using a 90% confidence level.

a.) State the random variables and the parameters in words.

   =

=

=

=

b.)          State and check the assumptions for confidence interval:

c.)           Find the sample statistics and confidence interval

Sample Proportion:

Confidence Interval:

d.)          Statistical Interpretation:

e.)          Real World Interpretation:

Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. The students in group 1 were asked to spend 5 minutes thinking about what it would mean to be a​ professor, while the students in group 2 were asked to think about soccer hooligans. These pretest thoughts are a form of priming. The 200 students in group 1 had a mean score of 23.6 with a standard deviation of 4.5​, while the 200 students in group 2 had a mean score of 17 with a standard deviation of 3.9. Complete parts ​(a) and ​(b) below.

a.) Determine the 90​% confidence interval for the difference in​ scores, μ1−μ2. Interpret the interval.

the upper bound is ?

the lower bound is ?

The classrooms at the Redman Academy consist of cramped tables that seat 3 people. The probability of being-left handed is 26%, and left-handed test takers need to sit in the far-left seat, otherwise, they constantly bump elbows with the person next to them causing complaints.

A) What is the probability that no one in a group of 3 students is left-handed?

B) What is the probability that only 1 person in the group of 3 students is left-handed?

C) What is the probability that no one at a table will complain during a test if I randomly seat three students?

D) I have 9 students in my class, 2 of which are left-handed. If I have exactly 3 tables and randomly seat the students, what is the probability of no complaints?