Each of the four independent situations below describes a sales-type lease in which annual lease payments of $10,000 are payable at the beginning of each year. Each is a finance lease for the lessee. (FV of $1, PV of $1, FVA of $1, PVA of $1, FVAD of $1 and PVAD of $1) (Use appropriate factor(s) from the tables provided.)

  
Determine the following amounts at the beginning of the lease (Round your final answers to nearest whole dollar.):

You are studying the reaction of iodine with a ketone to produce iodoketone with the following equation:

            I₂ + ketone → iodoketone + H⁺ + I^-

Data for initial rates and concentrations are given in the table below:

-d[I₂]/dt                        [I₂]                   [ketone]                        [H⁺]

mol^-1 L s^-1                     M                     M                                 M

7 x 10^-5                         5 x 10^-4             0.2                               1.0 x 10^-2

7 x 10^-5                         3 x 10^-4             0.2                               1.0 x 10^-2

1.7 x 10^-5                      5 x 10^-4             0.5                               1.0 x 10^-2

5.4 x 10^-5                      5 x 10^-4             0.5                               3.2 x 10^-2

Calculate the average rate coefficient in te above question.

problem 3 (ii)

Michael consumes apples and pears. In year 1, apples cost $1 each, pears cost $2 each, Michael buys 4 apples and 2 pears in year 1. In year 2, apples cost $2 each and pears cost $1 each, and michael buys 2 apples and 4 pears.

Define the implicit price deflator as nominal spending divided by real spending; compute the deflator for each year. How does the deflator change from year 1 to year 2?

For the following scores construct a frequency distribution table with columns x, f, rf, cf, and c% x: 6, 4, 3, 5, 4, 2, 4, 5, 4, 6, 1, 4, 5, 2

Two waves traveling in opposite directions on a stretched rope interfere to give the standing wave described by the following wave function:

y(x,t) = 4 sin⁡(2πx) cos⁡(120πt),

where, y is in centimetres, x is in meters, and t is in seconds. The rope is two meters long, L = 2 m, and is fixed at both ends.

A)Which of the following represents the two individual waves, y1 and y2, which produce the above standing waves:

1)y1 = 2 sin⁡(2πx ‒ 120πt), and y2 = 2 sin⁡(2πx ‒ 120πt)

2)y1 = 4 sin⁡(2πx ‒ 120πt), and y2 = 4 sin⁡(2πx + 120πt)

3)y1 = 2 sin⁡(2πx ‒ 120πt), and y2 = 2 sin⁡(2πx + 120πt)

4)y1 = 1 cos⁡(2πx ‒ 120πt), and y2 = 3 cos⁡(120πx + 2πt)

5)y1 = 1 sin⁡(2πx ‒ 120πt), and y2 = 3 sin⁡(2πx + 120πt + π)

Other:

B)The distance between two successive antinodes is:

1) d_AA = 0.25 m

2) d_AA = 0.15 m

3) d_AA = 1 m

4) d_AA = 0.5m

5) d_AA = 2 m

Other:

C) The fundamental resonance frequency on this rope is:

1) f1 = 60 Hz

2) f1 = 30 Hz

3) f1 = 25 Hz

4) f1 = 20 Hz

5) f1 = 15 Hz

Other:

C)The maximum transverse speed of an element on the rope located at the position x = 1.5 m is:

1) v_(y,max) = 480 π cm/s

2) v_(y,max) = 240 cm/s

3) v_(y,max) = 0 cm/s

4) v_(y,max) = 120 π cm/s

5) v_(y,max) = 60 cm/s

Other:

D)In terms of the oscillation period, T, at which of the following times would all elements on the string have a zero vertical displacement, y(x,t) = 0, for the first time:

1) t = T/8

2) t = T/4

3) t = T/2

4) t = 3T/4

5) t = T

Other:

e) If the oscillation frequency is decreased by a factor of four, f_new = f/4, while keeping the tension force, the length of the rope, and the linear mass density constants, then how many loops would appear on the rope?

1) One loop

2) Two loops

3) Three loops

4) Four loops

5) No loops appear, because the conditions are not satisfied for the standing waves to exist.

Please make sure that these infix and postfix equations have these answers nothing else:

Infix:

(3 * 4 - (2 + 5)) * 4 / 2 = valid expression

10 + 6 * 11 -(3 * 2 + 14) / 2 = valid expression

Postfix:

9 3 / 6 / 4 * 10 - = -8

9 3 / 6 / 4 * -10 - = 12

(a) Using java.util.stack to write a java program to validate and calculate the result of each arithmetic Expression from input file (infix.dat). All equations from the input file are in traditional infix notation. Display each expression first. Then, if the arithmetic expression is not valid, display “Invalid expression ” message otherwise display the result of the calculation.

(b) Using java.util.Stack and java.util.StringTokenizer to write a java program to validate and calculate postfix expression from the input data file - postfix.dat

infix.dat

5 * 6 + 4
3 - 2 +
( 3 * 4 - (2 + 5)) * 4 / 2
10 + 6 * 11 -(3 * 2 + 14) / 2
2 * (12 + (3 + 5 ) * 2

postfix.dat

5 2 + 8 5 - *
2 4 - 5 2 * +
5 2 6 3 - * + 4 + 2 3 1 + * 7
5 0 /
9 3 / 6 / 4 * 10 - 3 / +
9 3 / 6 / 4 * 10 -
5 2 6 3 - * + 4 + 2 3 1 + * 7 - *
9 3 / 6 / 4 * -10 -

During the past 10 years, the percent returns on two mutual funds (aggressive and passive) expressed in percentages were as follows:

Note that this is a sample of returns.

a) Compute the expected return for the two funds. Round your answers to two decimal places.

Aggressive =  

Passive =  

b) Compute the variance and standard deviation of the returns of the two funds. Round your answers to two decimal places.

Variance:

Aggressive =  

Passive =  

Standard Deviation:

Aggressive =  %

Passive =  %

Programming language in Python

Suppose, for Jane, n1 = 3, n2 = 4, and n3 = 5. Also suppose, Jane iterates the number from 1 to 15.
At the beginning, Jane sets count to 0, and then proceeds iterating the number from 1 to 15 and for each iteration does the following:

for 1, count is increased by 1 because it is not divisible by 3, 4, and 5; count is now: 1
for 2, count is increased by 2 because it is not divisible by 3, 4, and 5; count is now: 3
for 3, count is increased by 1 because it is divisible by 3; count is now: 4
for 4, count is increased by 2 because it is divisible by 4; count is now: 6
for 5, count is increased by 3 because it is divisible by 5; count is now: 9
for 6, count is increased by 1 because it is divisible by 3; count is now: 10
for 7, count is increased by 7 because it is not divisible by 3, 4, and 5; count is now: 17
for 8, count is increased by 2 because it is divisible by 4; count is now: 19
for 9, count is increased by 1 because it is divisible by 3; count is now: 20
for 10, count is increased by 3 because it is divisible by 5; count is now: 23
for 11, count is increased by 11 because it is not divisible by 3, 4, and 5; count is now: 34

for 12, count is increased by 1 because it is divisible by 3, count is increased by 2 because it is divisible by 4; count is now: 37

for 13, count is increased by 13 because it is not divisible by 3, 4, and 5; count is now: 50
for 14, count is increased by 14 because it is not divisible by 3, 4, and 5; count is now: 64

for 15, count is increased by 1 because it is divisible by 3, count is increased by 3 because it is divisible by 5; count is now: 68

The final answer should be: 68


Please note: for 12, because it was divisible by both n1, and n2, both 1 and 2 were added. Similarly,
for 15, because it was divisible by both n1 and n3, both 1 and 3 were added.

The Salem Board of Education wants to evaluate the efficiency of the town’s four elementary schools. The three outputs of the schools are

■   output 1 = average reading score
■   output 2 = average mathematics score

■   output 3 = average self-esteem score

The three inputs to the schools are

■   input 1 = average educational level of mothers
(defined by highest grade completed: 12 = high
school graduate; 16 = college graduate, and so on)

■   input 2 = number of parent visits to school (per child)

■   input 3 = teacher-to-student ratio

The relevant information for the four schools is given in the file P04_42.xlsx. Determine which (if any) schools are inefficient.

Plot MATINGS by AGE, then add a least squares line. Include your plot.

Is there evidence that modeling matings using a linear regression with age might not be appropriate? Explain. (Hint: Check for a linear trend and for constant variance about the linear fit.)