Caspian Sea Drinks is considering buying the J-Mix 2000. It will allow them to make and sell more product. The machine cost $1.95 million and create incremental cash flows of $547,959.00 each year for the next five years. The cost of capital is 11.75%. What is the internal rate of return for the J-Mix 2000?

Caspian Sea Drinks is considering buying the J-Mix 2000. It will allow them to make and sell more product. The machine cost $1.54 million and create incremental cash flows of $437,699.00 each year for the next five years. The cost of capital is 9.71%. What is the internal rate of return for the J-Mix 2000?

You have the following information from 2000 pairs of randomly picked numbers from 0-9:

Slope: 0.00667162

Intercept: 4.47354107

Correlation: 0.00668018

P-value of slope: 0.76527333

How do you explain the results you got for the 2000 pairs? (Discuss the slope, intercept, correlation, p-value.)​

Based on this code:

CREATE TABLE DEPARTMENT (

DepartmentName Char(35) NOT NULL,

BudgetCode Char(30) NOT NULL,

OfficeNumber Char(15) Not Null,

DepartmentPhone Char(12) NOT NULL,

CONSTRAINT DEPARTMENT_PK primary key(DepartmentName)

);

CREATE TABLE EMPLOYEE(

EmployeeNumber Int NOT NULL AUTO_INCREMENT,

FirstName Char(25) NOT NULL,

LastName Char(25) NOT NULL,

Department Char(35) NOT NULL DEFAULT 'Human Resources',

Position Char(35) NULL,

Supervisor Int NULL,

OfficePhone Char(12) NULL,

EmailAddress VarChar(100) NOT NULL UNIQUE,

CONSTRAINT EMPLOYEE_PK PRIMARY KEY(EmployeeNumber),

CONSTRAINT EMP_DEPART_FK FOREIGN KEY(Department)

REFERENCES DEPARTMENT(DepartmentName)

ON UPDATE CASCADE,

CONSTRAINT EMP_SUPER_FK FOREIGN KEY(Supervisor)

REFERENCES EMPLOYEE(EmployeeNumber)

);

ALTER TABLE EMPLOYEE AUTO_INCREMENT=1;

CREATE TABLE PROJECT(

ProjectID Int NOT NULL AUTO_INCREMENT,

ProjectName Char(50) NOT NULL,

Department Char(35) NOT NULL,

MaxHours Numeric(8,2) NOT NULL DEFAULT 100,

StartDate Date NULL,

EndDate Date NULL,

CONSTRAINT PROJECT_PK PRIMARY KEY(ProjectID),

CONSTRAINT PROJ_DEPART_FK FOREIGN KEY(Department)

REFERENCES DEPARTMENT(DepartmentName)

ON UPDATE CASCADE

);

ALTER TABLE PROJECT AUTO_INCREMENT=1000;

CREATE TABLE ASSIGNMENT (

ProjectID Int NOT NULL,

EmployeeNumber Int NOT NULL,

HoursWorked Numeric(6,2) NULL,

CONSTRAINT ASSIGNMENT_PK PRIMARY KEY(ProjectID, EmployeeNumber),

CONSTRAINT ASSIGN_PROJ_FK FOREIGN KEY(ProjectID)

REFERENCES PROJECT(ProjectID)

ON UPDATE NO ACTION

ON DELETE CASCADE,

CONSTRAINT ASSIGN_EMP_FK FOREIGN KEY(EmployeeNumber)

REFERENCES EMPLOYEE(EmployeeNumber)

ON UPDATE NO ACTION

How would I retrieve these commands?

Retrieve all the information for the assignments with hours worked less than 40.

Retrieve all the columns for employee(s) whose first name starts with M or J and ends with n

or e.

Retrieve all the columns for employee(s) whose first name is 5 letters.

Retrieve all the columns for employee(s) whose first name is 5 letters and en

ds with an a.

Retrieve all the columns for employee(s) whose first name is 5 letters and starts with a J and

ends with an a.

when 1.6038 g of an organic iron compound Fe, C, H and O was burned in O2, 2.9998 g of CO2 and 0.85850 g of H2O were produced. In a separate experiment to determine the mass percent of iron, 0.2726 g of the compound yielded 0.06159 g of Fe2O3. What is the empirical formula of the compound?

When 1.661 grams of a hydrocarbon, C_xH_y, were burned in a combustion analysis apparatus, 5.211grams of CO₂ and 2.134 grams of H₂O were produced.

In a separate experiment, the molar mass of the compound was found to be 42.08 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon.

Enter the elements in the order presented in the question.

Our favorite magic black box has given us the following percent composition: 6.00% Hydrogen, 63.56 % Carbon, 9.27% Nitrogen and 21.17% Oxygen. What is the empirical formula? Our second favorite magic box gives us the molecular mass of 453.54 g / mol ? What is the molecular formula?

The lifetimes of lightbulbs of a particular type are normally distributed with a mean of 400 hours and a standard deviation of 10 hours. What percentage of the bulbs have lifetimes that lie within 2 standard deviations to either side of the mean? Use the Empirical Rule and write your answer as a percent rounded to 2 decimal places.

Calculate the empirical forumla of your compound. Set the formula in the form Ni(Cl)x(NH3)y where x and y are determined from their titration results.

From my titration results:

% mass of Ni+2= 25.8% (0.192mmol)

% mass of Cl- = 26.8% (0.315mmol)

% mass of NH3 = 45.4% (1.12mmol)