It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minutes per day that people spend standing or walking. Among mildly obese people, the mean number of minutes of daily activity (standing or walking) is approximately Normally distributed with 365365 minutes and standard deviation 6969 minutes. The mean number of minutes of daily activity for lean people is approximately Normally distributed with 528528 minutes and standard deviation 106106 minutes. A researcher records the minutes of activity for an SRS of 66 mildly obese people and an SRS of 66 lean people.

(a) What is the probability that the mean number of minutes of daily activity of the 66 mildly obese people exceeds 420420minutes? (Enter your answer rounded to four decimal places.)

probability:

(b) What is the probability that the mean number of minutes of daily activity of the 66 lean people exceeds 420420 minutes? (Enter your answer rounded to four decimal places.)

Question 1: A drive-in movie theatre charges viewers by the carload but keeps careful records of the number of people in each car. The probability distribution for the number of people in each car entering the drive-in is given in the table. x = (px) 1= 0.02 2= 0.30 3=0.10 4= 0.30 5= 0.20 6=0.08 a. Suppose two cars entering the drive-in are selected at random. Find the exact probability distribution for the maximum number of people in either one of the cars, M. (Show all your work in order to get full marks, i.e., show: 1. the total number of samples of two cars, 2. the list all the possible samples of two cars, the value of max, and the corresponding probability. 3. the exact distribution for the maximum number of people in either one of the cars). b. Find the mean, variance, and standard deviation of M.

Please provide answer with full details with equations! The one posted on Chegg already for this question is incorrect!

Consider a husband and wife with brown eyes who have 0.75 probability of having children with brown eyes, 0.125 probability of having children with blue eyes, and 0.125 probability of having children with green eyes.

(a) What is the probability that their first child will have green eyes and the second will not?

(b) What is the probability that exactly one of their two children will have green eyes?

(c) If they have 7 children, what is the probability that exactly 2 will have blue eyes?

(d) If they have 7 children, what is the probability that at least 2 will have green eyes?

(e) What is the probability that the first brown eyed child will be child number 3?

American Airlines' flights from Chicago to Atlanta are on time 70 % of the time. Suppose 9 flights are randomly selected, and the number on-time flights is recorded.
Round answers to 3 significant figures.

The probability that exactly 7 flights are on time is =

The probability that at most 3 flights are on time is =

The probability that at least 4 flights are on time is =

Problem Binomial Distribution: A consumer advocate claims that 80 percent of cable television subscribers are not satisfied with their cable service. In an attempt to justify this claim, a randomly selected sample of cable subscribers will be polled on this issue.

Suppose that the advocate’s claim is true, and suppose that a random sample of 25 cable subscribers is selected. Assuming independence, find:

(2) The probability that more than 20 subscribers in the sample are not satisfied with their service. Minitab instructions: Go to Calc > select Probability Distributions > select Binomial > select Cumulative probability > Number of Trials insert 25 > Event Probability insert “.8” > Input Constant insert “20.” Click OK.Paste your Minitab results here and then show your work to calculate P(x > 20) = 1 – P(x ≤ 20) to get your final answer:

(3) The probability that between 20 and 24 (inclusive) subscribers in the sample are not satisfied with their service.

(A) Miniab instructions: Go to Calc > select Probability Distributions > select Binomial > select Cumulative probability > Number of Trials insert 25 > Event Probability insert “.8” > Input Constant insert “19.” Click OK.

(B) Minitab instructions: Go to Calc > select Probability Distributions > select Binomial > select Cumulative probability > Number of Trials insert 25 > Event Probability insert “.8” > Input Constant insert “24.” Click OK. Paste each of your Minitab results here and then show your work to calculate P(20 ≤ x ≤ 24) = P( x≤ 24) – P(x≤ 19) to get your final answer:

(4)  The probability that exactly 24 subscribers in the sample are not satisfied with their service.Paste your Minitab results here:

c) Suppose that when we survey 25 randomly selected cable television subscribers, we find that 15 are actually not satisfied with their service. Using a probability you found in this exercise as the basis for your answer, do you believe the consumer advocate’s claim? Explain your answer here:

Suppose a poll of 20 voters is taken in a large city. The purpose is to determine x, the number who favor a certain candidate for mayor. Suppose that 40% of all the city’s voters favor the candidate.

a. Find the mean and standard deviation of x.

b. What is the probability that x <=10.

c. Find the probability that x > 12.

d. Find the probability that x = 11

e. Graph the probability distribution of x.

1. What are the business reasons behind the offshoring of shoe production from the U.S. to other countries?

2. Who wins when there is free trade? Who loses? What is government's role in the trade arena?

MODEL

X Y Z

NUMBER OF DEFECTIVE CARS SOLD 50 100 350

TOTAL NUMBER OF CARS SOLD 150 250 600

Suppose that we randomly select 2 different (First and Second) consumers each of whom purchased a new MERCEDES car in 2020. Given this experiment answer all of the following 10 questions.

Q1) What is the probability of the first consumer’s car to be MODEL X?

Q2)What is the probability of the first consumer’s car to be either MODEL Y or MODEL Z?

Q3)What is the probability of the second consumer’s car to be either MODEL X or MODEL Z?

Q4) What is the probability of the first consumer’s car to be either DEFECTIVE or MODEL Y?

Q5) What is the probability of the second consumer’s car to be either NON-DEFECTIVE or MODEL Z?

Q6)If the second consumer’s car is MODEL Y, what is the probability that İt is NON-DEFECTIVE?

Q7) If the first consumer’s car is NON-DEFECTIVE what is the probability that it is MODEL Z?

Q8) What is the probability of the cars of both of these 2 consumers to be DEFECTIVE?

Q9)If the car of the first consumer is MODEL Z what is the probability of the car of the second consumer to be MODEL X?

Q10) If the car of the second consumer is DEFECTIVE, what is the probability of the car of the first consumer to be MODEL Y?

Assume that SAT scores are normally distributed with a mean of 1000 and a standard deviation of 150. Use this information to answer the following questions. Round final answers to the nearest whole number.

What is the lowest SAT score that can be in the top 10% of testers?

What is the highest SAT score that can be in the bottom 5% of testers?

Between which two SAT scores do the middle 50% of testers lie?