Let x be a random variable that represents the weights in kilograms (kg) of healthy adult female deer (does) in December in a national park. Then x has a distribution that is approximately normal with mean ? = 64.0 kg and standard deviation ? = 8.3 kg. Suppose a doe that weighs less than 55 kg is considered undernourished.

(a) What is the probability that a single doe captured (weighed and released) at random in December is undernourished? (Round your answer to four decimal places.)


(b) If the park has about 2200 does, what number do you expect to be undernourished in December? (Round your answer to the nearest whole number.)
does

(c) To estimate the health of the December doe population, park rangers use the rule that the average weight of n = 60 does should be more than 61 kg. If the average weight is less than 61 kg, it is thought that the entire population of does might be undernourished. What is the probability that the average weight  x for a random sample of 60 does is less than 61 kg (assuming a healthy population)? (Round your answer to four decimal places.)

(d) Compute the probability that  x < 65 kg for 60 does (assume a healthy population). (Round your answer to four decimal places.)

Suppose park rangers captured, weighed, and released 60 does in December, and the average weight was  x = 65 kg. Do you think the doe population is undernourished or not? Explain.

Since the sample average is below the mean, it is quite unlikely that the doe population is undernourished.

Since the sample average is above the mean, it is quite unlikely that the doe population is undernourished.    

Since the sample average is above the mean, it is quite likely that the doe population is undernourished.

Since the sample average is below the mean, it is quite likely that the doe population is undernourished.

Hotel Fawlty Towers is (as expected) not doing so well. In total, there are fixed joint costs of 4,800,000 (converted to SEK) per year. On average, you have separate income (= sales price) of SEK 1200 per guest per night. The special cost for each guest and night is 180 SEK. In total, there are 3100 overnight guests per year but a capacity of 6500 per year. The worst is during the weekends where you only have 120 overnight guests per year (included in the 3100 guests per year). Now the hotel owner, Basil, has been on a course in Revenue Management and learned there that you should put a lower price on the weekends to fill the hotel better. Together with the regular guest and strategist Major Gowen, Basil estimates that if the price per guest and night is set to SEK 700, the number of overnight stays at weekends will increase to 350 per year and if the price is set to SEK 500, the number of overnight stays at weekends will be a total of 800 per year. The price during other days does not change, nor the number of guests.

SEK = Swedish kronor. Although hotels and people are taken from the English series "Pang in the building", we are based on Swedish conditions regarding VAT rate and currency.

a)Should you lower the price on weekends? If so to SEK 700 or SEK 500? Show total results for the different options and compare with not lowering the weekend price! (6p)

b) In order to obtain additional revenue, you plan to sell various small items at the reception. Basil has heard that the gross profit margin for these goods should be 60%. What then is the selling price of a toothbrush the hotel buys for 8,00 SEK? Don't forget to add VAT with a 25% surcharge!

Let x be a random variable that represents the weights in kilograms (kg) of healthy adult female deer (does) in December in a national park. Then x has a distribution that is approximately normal with mean μ = 68.0 kg and standard deviation σ = 7.8 kg. Suppose a doe that weighs less than 59 kg is considered undernourished.

(a) What is the probability that a single doe captured (weighed and released) at random in December is undernourished? (Round your answer to four decimal places.)


(b) If the park has about 2350 does, what number do you expect to be undernourished in December? (Round your answer to the nearest whole number.)
does

(c) To estimate the health of the December doe population, park rangers use the rule that the average weight of n = 60 does should be more than 65 kg. If the average weight is less than 65 kg, it is thought that the entire population of does might be undernourished. What is the probability that the average weight

x

for a random sample of 60 does is less than 65 kg (assuming a healthy population)? (Round your answer to four decimal places.)


(d) Compute the probability that

x < 69.8 kg for 60 does (assume a healthy population). (Round your answer to four decimal places.)


Suppose park rangers captured, weighed, and released 60 does in December, and the average weight was

x = 69.8 kg. Do you think the doe population is undernourished or not? Explain.

Since the sample average is above the mean, it is quite unlikely that the doe population is undernourished.

Since the sample average is below the mean, it is quite likely that the doe population is undernourished.   

Since the sample average is above the mean, it is quite likely that the doe population is undernourished

.Since the sample average is below the mean, it is quite unlikely that the doe population is undernourished.

I am supposed to answer these conceptual questions with this lab simulator, but I can never get the simulator to work https://phet.colorado.edu/en/simulation/legacy/energy-skate-park

Help please?

Energy State Park Lab Handout

Click on the “Energy State Park Simulation” link to perform simulations in the setup satisfying the given conditions.

Upon opening the simulation, the skate should be alternating between the walls of the skate park with no friction added and with Earth’s gravity. Click on the Show Pie Chart under the Energy Graphs section.

1. With no friction, will his motion every stop?

2. What principle can be applied to this situation?

3. What type of forces are applied here? (Conservative/Non-conservative)

4. What happens to the skater’s potential energy has he falls down a wall to the valley? What about when he moves up a wall from the valley?

5. What happens to the skater’s kinetic energy has he falls down a wall to the valley? What about when he moves up a wall from the valley?

6. Will any kinetic energy be transformed into thermal energy? If so , why? If not, why?

7. Where does the skater have the maximum potential energy?

8. Where does the skater have the maximum kinetic energy?

Now change the coefficient of friction to half way between None and Lots.

1. Are there any non-conservative forces in this simulation? If so what force?

2. With friction, will the skater ever stop?

3. Would thermal energy be created with this situation?

Conceptual Questions:

1. What is the formula for kinetic energy?

2. What is the formula for gravitational potential energy?

3. If the 75 kg skater reaches a maximum height of 5 feet, what is his maximum gravitational potential energy? (Hint: remember to convert to meters).

4. Is gravitational potential energy a conservative or non-conservative force? Is friction force a conservative or non-conservation force?

You are a data analyst with strong backgrounds in database design and management. In fact, you have learned from education, mentors, and experience the art of collecting data and transforming data into business intelligence and your experience in database design and management complements your abilities to analyze data. Your hypothetical employer, Park University, is in the process planning a new employee payroll database and has asked you for assistance. The database will be standalone but will need to have ability to communicate with other ODBC and SQL Server databases. The overall purpose of the database will be to input employee data for 100-150 employees. The database will need to input time and process data needed to document payroll and to create payroll checks. Park University at this point needs to understand and review options so that cost to develop and maintain this payroll database are kept at a minimum but without compromising security. Park University has requested information and has asked you to address the following questions: Would a full-scale Database Management System (DBMS) or Relational Database Management Systems (RDBMS) be required in this case? Discuss and defend your answer in scholarly detail!! Could Microsoft Access be a good option in this case? Discuss and defend your answer in scholarly detail!! Could even Microsoft Excel be used in this case maybe as a secondary database support application for further data analysis and statistical models? Discuss and defend your answer in scholarly detail!! What Systems Development Life Cycle methodology would you suggest in this case for the overall planning, design, implementation, and maintenance of this database? Discuss and defend your answer in scholarly detail!! What else might you need to cover to help Park University determine what type of database to consider for the new payroll database? Include any other important conclusions or content you see fit to support this assignment.

Let x be a random variable that represents the weights in kilograms (kg) of healthy adult female deer (does) in December in a national park. Then x has a distribution that is approximately normal with mean μ = 55.0 kg and standard deviation σ = 8.2 kg. Suppose a doe that weighs less than 46 kg is considered undernourished.

(a) What is the probability that a single doe captured (weighed and released) at random in December is undernourished? (Round your answer to four decimal places.)


(b) If the park has about 2600 does, what number do you expect to be undernourished in December? (Round your answer to the nearest whole number.)
does

(c) To estimate the health of the December doe population, park rangers use the rule that the average weight of n = 70 does should be more than 52 kg. If the average weight is less than 52 kg, it is thought that the entire population of does might be undernourished. What is the probability that the average weight

x

for a random sample of 70 does is less than 52 kg (assuming a healthy population)? (Round your answer to four decimal places.)


(d) Compute the probability that

x

< 56.9 kg for 70 does (assume a healthy population). (Round your answer to four decimal places.)


Suppose park rangers captured, weighed, and released 70 does in December, and the average weight was

x

= 56.9 kg. Do you think the doe population is undernourished or not? Explain.

Since the sample average is below the mean, it is quite unlikely that the doe population is undernourished. Since the sample average is below the mean, it is quite likely that the doe population is undernourished.     Since the sample average is above the mean, it is quite likely that the doe population is undernourished. Since the sample average is above the mean, it is quite unlikely that the doe population is undernourished.

Let x be a random variable that represents the weights in kilograms (kg) of healthy adult female deer (does) in December in a national park. Then x has a distribution that is approximately normal with mean μ = 58.0 kg and standard deviation σ = 6.4 kg. Suppose a doe that weighs less than 49 kg is considered undernourished.

(a) What is the probability that a single doe captured (weighed and released) at random in December is undernourished? (Round your answer to four decimal places.)


(b) If the park has about 2300 does, what number do you expect to be undernourished in December? (Round your answer to the nearest whole number.)
does

(c) To estimate the health of the December doe population, park rangers use the rule that the average weight of n = 40 does should be more than 55 kg. If the average weight is less than 55 kg, it is thought that the entire population of does might be undernourished. What is the probability that the average weight

x

for a random sample of 40 does is less than 55 kg (assuming a healthy population)? (Round your answer to four decimal places.)


(d) Compute the probability that

x

< 59.9 kg for 40 does (assume a healthy population). (Round your answer to four decimal places.)


Suppose park rangers captured, weighed, and released 40 does in December, and the average weight was

x

= 59.9 kg. Do you think the doe population is undernourished or not? Explain.

Since the sample average is above the mean, it is quite unlikely that the doe population is undernourished.Since the sample average is below the mean, it is quite unlikely that the doe population is undernourished.    Since the sample average is below the mean, it is quite likely that the doe population is undernourished.Since the sample average is above the mean, it is quite likely that the doe population is undernourished.

Let x be a random variable that represents the weights in kilograms (kg) of healthy adult female deer (does) in December in a national park. Then x has a distribution that is approximately normal with mean μ = 50.0 kg and standard deviation σ = 8.6 kg. Suppose a doe that weighs less than 41 kg is considered undernourished.

(a) What is the probability that a single doe captured (weighed and released) at random in December is undernourished? (Round your answer to four decimal places.)

(b) If the park has about 2700 does, what number do you expect to be undernourished in December? (Round your answer to the nearest whole number.) does

(c) To estimate the health of the December doe population, park rangers use the rule that the average weight of n = 65 does should be more than 47 kg. If the average weight is less than 47 kg, it is thought that the entire population of does might be undernourished. What is the probability that the average weight x for a random sample of 65 does is less than 47 kg (assuming a healthy population)? (Round your answer to four decimal places.)

(d) Compute the probability that x < 51.6 kg for 65 does (assume a healthy population). (Round your answer to four decimal places.)

Suppose park rangers captured, weighed, and released 65 does in December, and the average weight was x = 51.6 kg. Do you think the doe population is undernourished or not? Explain.

Since the sample average is above the mean, it is quite unlikely that the doe population is undernourished.

Since the sample average is above the mean, it is quite likely that the doe population is undernourished.

Since the sample average is below the mean, it is quite unlikely that the doe population is undernourished.

Since the sample average is below the mean, it is quite likely that the doe population is undernourished.

Let x be a random variable that represents the weights in kilograms (kg) of healthy adult female deer (does) in December in a national park. Then x has a distribution that is approximately normal with mean μ = 60.0 kg and standard deviation σ = 8.6 kg. Suppose a doe that weighs less than 51 kg is considered undernourished.

(a) What is the probability that a single doe captured (weighed and released) at random in December is undernourished? (Round your answer to four decimal places.)


(b) If the park has about 2900 does, what number do you expect to be undernourished in December? (Round your answer to the nearest whole number.)
does

(c) To estimate the health of the December doe population, park rangers use the rule that the average weight of n = 65 does should be more than 57 kg. If the average weight is less than 57 kg, it is thought that the entire population of does might be undernourished. What is the probability that the average weight x for a random sample of 65 does is less than 57 kg (assuming a healthy population)? (Round your answer to four decimal places.)


(d) Compute the probability that x< 61 kg for 65 does (assume a healthy population). (Round your answer to four decimal places.)


Suppose park rangers captured, weighed, and released 65 does in December, and the average weight was x= 61 kg. Do you think the doe population is undernourished or not? Explain.

Since the sample average is above the mean, it is quite likely that the doe population is undernourished.

Since the sample average is above the mean, it is quite unlikely that the doe population is undernourished.    

Since the sample average is below the mean, it is quite likely that the doe population is undernourished.

Since the sample average is below the mean, it is quite unlikely that the doe population is undernourished.

Let x be a random variable that represents the weights in kilograms (kg) of healthy adult female deer (does) in December in a national park. Then x has a distribution that is approximately normal with mean μ = 52.0 kg and standard deviation σ = 9.0 kg. Suppose a doe that weighs less than 43 kg is considered undernourished.

(a) What is the probability that a single doe captured (weighed and released) at random in December is undernourished? (Round your answer to four decimal places.)


(b) If the park has about 2100 does, what number do you expect to be undernourished in December? (Round your answer to the nearest whole number.)
does

(c) To estimate the health of the December doe population, park rangers use the rule that the average weight of n = 70 does should be more than 49 kg. If the average weight is less than 49 kg, it is thought that the entire population of does might be undernourished. What is the probability that the average weight

x

for a random sample of 70 does is less than 49 kg (assuming a healthy population)? (Round your answer to four decimal places.)


(d) Compute the probability that

x

< 53.6 kg for 70 does (assume a healthy population). (Round your answer to four decimal places.)


Suppose park rangers captured, weighed, and released 70 does in December, and the average weight was

x

= 53.6 kg. Do you think the doe population is undernourished or not? Explain.

Since the sample average is above the mean, it is quite unlikely that the doe population is undernourished.Since the sample average is above the mean, it is quite likely that the doe population is undernourished.    Since the sample average is below the mean, it is quite unlikely that the doe population is undernourished.Since the sample average is below the mean, it is quite likely that the doe population is undernourished.