The CEO of a company wants to estimate the percent of employees that use company computers to go on Facebook during work hours. He selects a random sample of 200 of the employees and finds that 76 of them logged onto Facebook that day. Construct a 95% confidence interval for the population proportion.

Answer the following questions in the Answer box.

a. i) Sample proportion = ?    a. ii) critical value Z = ? a. iii) Standard error = ?    a. iv) Margin of error = ?    a. v) Lower limit = ?    a. vi) upper limit = ?

The CEO of a company wants to estimate the percent of employees that use company computers to go on Facebook during work hours. He selects a random sample of 200 of the employees and finds that 76 of them logged onto Facebook that day. Construct a 95% confidence interval for the population proportion.

Answer the following questions

a. i) Sample proportion = ?    a. ii) critical value Z = ? a. iii) Standard error = ?    a. iv) Margin of error = ?    a. v) Lower limit = ?    a. vi) upper limit = ?

Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is 169000 dollars. Assume the standard deviation is 43000 dollars. Suppose you take a simple random sample of 77 graduates. Find the probability that a single randomly selected policy has a mean value between 168019.9 and 175860.4 dollars. P(168019.9 < X < 175860.4) = (Enter your answers as numbers accurate to 4 decimal places.) Find the probability that a random sample of size n = 77 n=77 has a mean value between 168019.9 and 175860.4 dollars. P(168019.9 < M < 175860.4) = (Enter your answers as numbers accurate to 4 decimal places.)

Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is 121000 dollars. Assume the standard deviation is 41000 dollars. Suppose you take a simple random sample of 79 graduates.

Find the probability that a single randomly selected salary exceeds 117000 dollars.
P(X > 117000) =

Find the probability that a sample of size n=79 is randomly selected with a mean that exceeds 117000 dollars.
P(M > 117000) =

Enter your answers as numbers accurate to 4 decimal places.

Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is $156,000. Assume the standard deviation is $42,000. Suppose you take a simple random sample of 49 graduates. Round all answers to four decimal places if necessary.

1. What is the distribution of XX? XX ~ N(,)
2. What is the distribution of ¯xx¯? ¯xx¯ ~ N(,)
3. For a single randomly selected graduate, find the probability that her salary is between $150,400 and $159,100.
4. For a simple random sample of 49 graduates, find the probability that the average salary is between $150,400 and $159,100.
5. For part d), is the assumption of normal necessary? NoYes

Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is 160000 dollars. Assume the standard deviation is 42000 dollars. Suppose you take a simple random sample of 100 graduates.

Find the probability that a single randomly selected policy has a mean value between 155800 and 157900 dollars. P(155800 < X < 157900) = (Enter your answers as numbers accurate to 4 decimal places.)

Find the probability that a random sample of size n = 100 n=100 has a mean value between 155800 and 157900 dollars. P(155800 < M < 157900) =

(Enter your answers as numbers accurate to 4 decimal places.)

Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is 190000 dollars. Assume the standard deviation is 39000 dollars. Suppose you take a simple random sample of 96 graduates. Find the probability that a single randomly selected salary has a mean value between 184029.4 and 194776.5 dollars.

P(184029.4 < X < 194776.5) = (Enter your answers as numbers accurate to 4 decimal places.) Find the probability that a random sample of size n = 96 has a mean value between 184029.4 and 194776.5 dollars.

P(184029.4 < ¯ x < 194776.5) = (Enter your answers as numbers accurate to 4 decimal places.)

Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is $128,000. Assume the standard deviation is $43,000. Suppose you take a simple random sample of 15 graduates. Round all answers to four decimal places if necessary.

1. What is the distribution of XX? XX ~ N(,)
2. What is the distribution of ¯¯¯XX¯? ¯¯¯XX¯ ~ N(,)
3. For a single randomly selected graduate, find the probability that her salary is between $119,846 and $126,097.
4. For a simple random sample of 15 graduates, find the probability that the average salary is between $119,846 and $126,097.
5. For part d), is the assumption of normal necessary? NoYes

Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is $167,000 dollars. Assume the standard deviation is $32,000. Suppose you take a simple random sample of 96 graduates.

1) What is the standard deviation of the sampling distribution for this situation? Round to four places. Show work and answer using proper notation.

2) Find the probability that a single randomly selected salary has a value between $172,552 and $178,104. Your write up should include all of the following:

• Define the variable you are using.
• Use correct notation to label all quantities.
• Show the calculations for the relevant z-scores using proper notation.
• State or show how you found your final probability. You can use tables or StatCrunch, just specify what you did.
• Write your answer using full and correct probability notation. Round to four places.

3) Find the probability that a random sample of size n=96n=96 has a mean value between $172,552 and $178,104.

• Define the variable you are using.
• Use correct notation to label all quantities.
• Show the calculations for the relevant z-scores using proper notation.
• State or show how you found your final probability. You can use tables or StatCrunch, just specify what you did.
• Write your answer using full and correct probability notation. Round to four places.

Write your answers in complete sentence form.

Please be correct because this homework is very important for me. Thanks