USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let x = number of prisoners out of five on parole who become repeat offenders.

(a) Find the probability that one or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.)


How does this number relate to the probability that none of the parolees will be repeat offenders?

This is five times the probability of no repeat offenders.These probabilities are the same.    This is twice the probability of no repeat offenders.These probabilities are not related to each other.This is the complement of the probability of no repeat offenders.

(b) Find the probability that two or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.)


(c) Find the probability that four or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.)


(d) Compute μ, the expected number of repeat offenders out of five. (Round your answer to three decimal places.)
μ =  prisoners

(e) Compute σ, the standard deviation of the number of repeat offenders out of five. (Round your answer to two decimal places.)
σ =  prisoners

USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let x = number of prisoners out of five on parole who become repeat offenders.

(a) Find the probability that one or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.)


How does this number relate to the probability that none of the parolees will be repeat offenders?

a.These probabilities are the same.

b.This is five times the probability of no repeat offenders.    

c.This is twice the probability of no repeat offenders.

d.These probabilities are not related to each other.

e.This is the complement of the probability of no repeat offenders.

(b) Find the probability that two or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.)


(c) Find the probability that four or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.)


(d) Compute μ, the expected number of repeat offenders out of five. (Round your answer to three decimal places.)
μ =
(e) Compute σ, the standard deviation of the number of repeat offenders out of five. (Round your answer to two decimal places.)
σ =

USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let x = number of prisoners out of five on parole who become repeat offenders.

x 0, 1, 2, 3, 4, 5

P(x) 0.212, 0.374, 0.224, 0.158, 0.031, 0.001

(a) Find the probability that one or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.)

How does this number relate to the probability that none of the parolees will be repeat offenders?

These probabilities are not related to each other.

This is five times the probability of no repeat offenders.

This is the complement of the probability of no repeat offenders.

These probabilities are the same.

This is twice the probability of no repeat offenders.

(b) Find the probability that two or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.)

(c) Find the probability that four or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.)

(d) Compute μ, the expected number of repeat offenders out of five. (Round your answer to three decimal places.) μ = prisoners

(e) Compute σ, the standard deviation of the number of repeat offenders out of five. (Round your answer to two decimal places.) σ = prisoners

USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let x = number of prisoners out of five on parole who become repeat offenders.

(a) Find the probability that one or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.)


How does this number relate to the probability that none of the parolees will be repeat offenders?

a) These probabilities are the same.

b) This is the complement of the probability of no repeat offenders.    

c) This is twice the probability of no repeat offenders.

d) These probabilities are not related to each other.

e) This is five times the probability of no repeat offenders.

(b) Find the probability that two or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.)


(c) Find the probability that four or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.)


(d) Compute μ, the expected number of repeat offenders out of five. (Round your answer to three decimal places.)
μ = prisoners

(e) Compute σ, the standard deviation of the number of repeat offenders out of five. (Round your answer to two decimal places.)
σ = prisoners

USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let x = number of prisoners out of five on parole who become repeat offenders.
x 0 1 2 3 4 5 P(x) 0.216 0.360 0.226 0.162 0.035 0.001
(a) Find the probability that one or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.) How does this number relate to the probability that none of the parolees will be repeat offenders? These probabilities are the same. This is twice the probability of no repeat offenders. This is five times the probability of no repeat offenders. This is the complement of the probability of no repeat offenders. These probabilities are not related to each other. Correct: Your answer is correct.
(b) Find the probability that two or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.)
(c) Find the probability that four or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.)
(d) Compute μ, the expected number of repeat offenders out of five. (Round your answer to three decimal places.) μ = prisoners
(e) Compute σ, the standard deviation of the number of repeat offenders out of five. (Round your answer to two decimal places.) σ = prisoners

USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let x = number of prisoners out of five on parole who become repeat offenders. x 0 1 2 3 4 5 P(x) 0.217 0.368 0.220 0.156 0.038 0.001 (a) Find the probability that one or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.) Incorrect: Your answer is incorrect. How does this number relate to the probability that none of the parolees will be repeat offenders? These probabilities are the same. This is twice the probability of no repeat offenders. This is five times the probability of no repeat offenders. This is the complement of the probability of no repeat offenders. These probabilities are not related to each other. (b) Find the probability that two or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.) (c) Find the probability that four or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.) (d) Compute μ, the expected number of repeat offenders out of five. (Round your answer to three decimal places.) μ = prisoners (e) Compute σ, the standard deviation of the number of repeat offenders out of five. (Round your answer to two decimal places.) σ = prisoners

the chance of winning a bet is 50%. If you win a bet, you receive the same amount that you put in. you plan on betting in a "double-down" loss scheme of $5/$10/$20/$40/$80/$160 for each consequtive loss. This equates to a total of $315. If you were to win a bet, the following bet will be $5. for example, if you lose 3 times on a row and win one the fourth, you would bet $5/$10/$20 /$40 and then the next bet return to $5. From this method, so long as you win at least one time prior to losing 6 in a row, you will win $5. However, if you were to ever have a 6 loss streak, this would mean you lose the $315 you started with. in order to not be at a defficiet, you would need to win at least 64 times prior to losing 6 in a row to reach $320 profit. this would mean that further wins are profit to the initial investment, even if one were to eventually receive a 6 loss streak. what is the probability of you profiting? in other words, what is the probability of winning 64 times without losing 6 times in a row

1. The Ganubrabdrab Company has determined that the number of telephone calls it receives each hour during holidays follows a normal distribution with a mean of 80,000 and a standard deviation of 35,000. Suppose 60 holiday hours are chosen at random.

1. What is the sampling distribution for the 60 hours?
2. What is the probability that for these 60 hours the number of incoming calls will be greater than 91,970?
3. What is the probability that for these 60 hours the number of incoming calls will be less than 75,000?
4. Construct the normal curve for the number of telephone calls received?

Suppose for your company, the probability an individual customer purchases something in-store is 0.74. The probability he or she purchases something online is 0.81. We have described a set of Bernoulli trials with this scenario:

            (a) There are two outcomes – purchase (a “success”) or no purchase,

            (b) The probability of a success is constant across trials, and

(c) Trials are independent of each other, assuming customers are not related or shopping together.

(1) What is the expected number of customers until the first one purchases something in-store?

(2) What is the expected number of customers until the first one purchases something online?

(3) What is the probability that the third customer is the first to purchase something in-store?

(4) What is the probability that the fifth customer is the first to purchase something online?

(5) What is the probability of exactly 7 of the next 12 customers purchasing something in-store?

(6) What is the probability that exactly 7 of the next 12 customers will purchase something online?

(7) What is the probability that no more than 6 of the next 9 customers will purchase something in-store?

(8) What is the probability that at least 8 of the next 11 customers will purchase something online?

Now we want to look at purchasing a specific item. Suppose the probability customers purchase that item in-store is 0.60, while the probability they purchase it online is 0.79.

(9) What is the probability exactly 4 out of the next 7 in-store customers will purchase that item?

(10) What is the probability at least 5 of the next 8 online customers will purchase that item?

(11) What is the probability the 4^th in-store customer will be the first to purchase that item?

(12) What is the probability no more than 5 of the next 11 online customers will purchase that item?

(13) What is the probability that at least 8 of the next 12 in-store customers will purchase that item?

(14) What is the probability the first online customer to purchase that item will be before the 5^th?

Suppose for your store, the mean number of customers at any time of the day is 4.8 (this would be λ). Determine the following probabilities. NOTE these are not based on Bernoulli trials.

(15) What is the probability of having no customers in the store at some point during the day?

(16) What is the probability of having at least 6 customers in the store at any given point?

(17) What is the probability of having no more than three customers in the store at any given point?

(18) What is the probability of having exactly 5 customers in the store at any given point?

(19) If I wanted to know the number of customers before the first one bought something, which model would I use?

            GEOMETRIC            BINOMIAL                POISSON            (circle one)

(20) If I wanted to know how many customers out of a certain number will buy something, which model would I use?

            GEOMETRIC            BINOMIAL                POISSON            (circle one)