if the mean=m,variance= v, observed value=o
we have four groups, g1 age 18-28,the observed resposibility of accident=127,m=0.809,v=0.848
for the same group the observed (not responsible) of accidents=192,m=1.22,v=1.849
group2 age 29-39 years ,o=155(responsible),m=0.5961,v=0.838
same group o=397 (not responsible),m=1.5269,v1.8336
group 3 age 40-50 o=127(responsible),m=0.635,v=0.841
same group o=277(not responsible),m=1.385,v=1.835
group 4 age >=51 ,o=54(responsible),m=0.446,v=0.849
same group o=54(not responsible),m=1.628,v=1.856
1-for the data shown which type of test we must use and why
2- using the test find the expected value for all responsible and not responsible accidents participations
3-if the test used is kai square find using (ovserved-expected)^2/expexted for all the data groups( resposible and not)
4- give an explanation or interpret the statistical test results for the significant values after finding p-value for the test
In: Statistics and Probability
class Node<V,P>
{
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public P priority;
public Node<V,P> next;
Node(V value, P priority)
{
this.value = value;
this.priority = priority;
}
}
class PriorityQueue<V,P>
{
private Node<V,P> head;
private Node<V,P> tail;
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public void Enqueue(V value, P priority)
{
In: Computer Science
2. I stand outside the student union and conduct a poll of passing students about their favorite fast food place. There are 6 response options = McDonald's, Wendy's, Burger King, Taco Bell, Popeye's, and Arby's. I also collect the student's year in school for demographic purposes - 5 levels - First Year, Sophomore, Junior, Senior, and Grad Student. I build a two-way table of this data to prepare to conduct a Chi-square analysis. How many degrees of freedom would my analysis have?
Group of answer choices:
6
35
20
5
1
3. The expected values for a Chi-Square Test of Independence come from:
Group of answer choices:
the population values
the marginals
a chi-square table
4. I conduct the Chi-Square test of independence for my Fast Food poll and obtain an observed Chi-square value of 22.55. The chisq-test() in R also reports a p-value of 0.3114. How do I interpret this result if my alpha is 0.05?
Group of answer choices
I fail to reject the null hypothesis and therefore determine that there is a significant association between fast food preference and class year.
I fail to reject the null hypothesis and therefore conclude that there is no association between class year and favorite fast food restaurant.
I reject the null hypothesis and conclude that there is a significant association between fast food preference and class year.
I reject the null hypothesis and conclude that there is no association between the variables fast food preference and class year.
5. My student union poll included another question regarding the preference for different dog breeds. I find a significant association between preferred dog breeds and gender of the students. I calculate a Cramer's V test and get a result of 0.05. What conclusion would I make about this result?
Group of answer choices:
The Cramer's V score disproves our statistical significant finding.
The Cramer's V value further proves that the result is significant.
The result was statistically significant, but not substantively significant.
6. I decide to conduct another poll outside the student union, and I want to ensure that my poll will have a low probability of Type II error and will be able to detect a difference with a large effect size. I run the following code:
pwr.chisq.test(w = 0.3, N=NULL, df = 20, sig.level = 0.05, power = 0.8)
I get the following output in R:
Chi squared power calculation
w = 0.3
N = 232.8977
df = 20
sig.level = 0.05
power = 0.8
What does this output tell me about how I need to design my next poll.
Group of answer choices
My new poll needs a power of 0.8 to have an effect size of 0.3.
A sample size of 230 should be sufficient for my poll.
Since I set my sample size at 233 I will achieve a power of 0.8.
I need a sample size of 233 students to obtain a result with the power I desire to have in my analysis.
7. The area under the curve of a normal distribution is equal to:
Group of answer choices
the mean of the distribution
a probability of 1.0
the standard deviation of the distribution.
the z-score
8. In my student union poll I asked students what they scored on the SAT. I know that the mean score of the UMD population is 1340 with a standard deviation of 222. My friend wants to know how her score of 1280 stacks up to the distribution of all scores at UMD.
What is her z-score?
Group of answer choices
-0.53
-1
0.27
-0.27
9. Another friend asked me to calculate his z-score so he could see how he compared to the distribution of SAT scores among UMD students. I found that his z-score was 0.33. What is the interpretation of his z-score?
Group of answer choices
He scored 3 SDs higher than the mean.
He scored better than 33% of students at UMD.
His SAT score shows he was 1/3 of an SD above the mean score.
He did worse than 33% of students at UMD.
10. We have more fitness test data from Vitor (who is male) and Manuela (who is female), who are applying to a military academy. Vitor did 50 push-ups in a minute, while Manuela only did 45.
We know that among previous applicants to the academy, the distribution of number of sit-ups is as follows:
Males have a mean of 60 and a standard deviation of 6.5.
Females have a mean of 40 and a standard deviation of 4.3.
What is the z-score for Manuela's result on the test?
Group of answer choices
1.16
1.69
-0.92
3.49
11. Vitor did 50 push-ups in a minute, while Manuela only did 45.
We know that among previous applicants to the academy, the distribution of number of sit-ups is as follows:
Males have a mean of 60 and a standard deviation of 6.5.
Females have a mean of 40 and a standard deviation of 4.3.
What is the z-score for Vitor's result on the test?
Group of answer choices:
0
2.33
-1.16
-1.54
12. Vitor did 50 push-ups in a minute, while Manuela only did 45.
We know that among previous applicants to the academy, the distribution of number of sit-ups is as follows:
Males have a mean of 60 and a standard deviation of 6.5.
Females have a mean of 40 and a standard deviation of 4.3.
Relative to their gender, who did better on the push-up test, Vitor or Manuela?
Group of answer choices:
Manuela
Vitor
In: Math
Question 1: Short Theory Questions
In: Accounting
The marketing manager of a national brand of flavored milk is considering her micro and macro environment in order to complete the situation analysis for this years marketing plan.
She notes some key points. Small traders are not consistently affording appropriate fridge space to flavored milks. Energy drinks are continuing to hold favour in the teen market. Young adults aged 18-25 are more conservative than their slightly older cohort 25-35. UHT or long life milk has processed to the point where taste tests show little noticeable difference. Having long life milk means the product can stay longer in the fridge before having it replaced. The main benefit of this is to the firm which can reduce production and distribution costs. This benefit has been derived through which macro environmental factor?
In: Operations Management
In your own words define and explain “marketing concept” and the
“4P’s.” Provide an example of a company that uses one or both
approaches.
• Define “marketing” and “sales” and explain how they are different
from one another. How are they dependent upon one another?
• Does “marketing” have a function in church operations? Explain
and support your answer.
Generational trends lead to distinctly different attitudes, values,
and behavioral patterns that must be considered when developing a
market plan.
• Identify the “generational cohorts” according to our text, and
explain their differences in values and motivational factors.
• Identify an advertisement or commercial that targets only one of
the generational groups. Describe the promotion in detail and
identify the intended group.
Explain how the Scripture verse “Jesus Christ is the same yesterday
and today and forever” (Heb. 13.8) relates to the “generational
cohort” discussion in the above exercise.
In: Accounting
Q 1. PLEASE answer all question because these only one question..... Thanks alot
In: Accounting
In a study concerning the relationship between the use of exogenous estrogens and subsequent risk of breast cancer, a sample of 1000 pre-menopausal women was followed for 8 years. The results are presented in the table below.
|
Breast Cancer |
|||
|
Estrogen Therapy |
Present |
Absent |
Total |
|
+ |
300 |
200 |
500 |
|
- |
100 |
400 |
500 |
|
Total |
400 |
600 |
1000 |
1.What kind of study is this?
2.Is this study prospective or retrospective?
3.The cumulative incidence of breast cancer among women receiving estrogen therapy is:
4.The cumulative incidence of breast cancer among women who did not receive estrogen therapy is:
5.The relative risk associated with estrogen therapy in this study is:
In: Nursing
Logic problems:
1. The argument “ All A are B. Some B are not C. // Some C are not A.” is of the form expressed in figure one.
A. True
B. False
2.Assume the Aristotelian Perspective, if the sentence “Some carrots are not tasty” is true, then what is the truth value of the following sentence " Some carrots are tasty. "
A. true
B. false
C. undetermined
D. none of the above
3. Which is the converse of the following sentence "No students at Miami are students at John Tyler"?
A. All students at Miami are students at John Tyler.
|
B. No students at John Tyler are students at Miami. C .Some students at Miami are not students are John Tyler. D.Some students at Miami are students at John Tyler. |
In: Psychology
In: Finance